(2x-3)^2-3^2=24
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(8486 - 2x) =320.26
8486 - 2x =8320
2x=8486-8320
2x=166
x=166:2
x=83
(8486-2x) :26=320 <=> 8486-2x=8320 <=> -2x=-166 <=> x=83
HỌC TỐT!!!
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ta có: 2022=2020+2 suy ra 2020x2022=2020x(2020+2) = 20202 +4040
ta có:2021=2020+1 suy ra 2021x2021=(2020+1)x(2020+1)=20202+2020+2020+1=20202+4041
Như vậy ta thấy 20202+4041>20202+4040
Vậy 2020x2022<2021x2021
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Vì \(x\in B\left(7\right)\)
\(\Rightarrow\)\(x\in\){ 0 ; 7 ; 14 ; 21 ; 28 ; 35 ; 42 ; 49 ; 56 ; 63 ; 70 ; 77 ; ..... }
mà \(x< 70\)
\(\Rightarrow\)\(x\in\){ 0 ; 7 ; 14 ; 21 ; 28 ; 35 ; 42 ; 49 ; 56 ; 63 ; 70 }
B(7) = { 0; 7; 14; 21; 28; 35; 42; 49; 56; 63; 70; ....}
Mà x<70 nên x ∈ { 0; 7; 14; 21; 28; 35; 42; 49; 56; 63 }
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\(A=1+5^3+5^6+...+5^{99}\)
\(5^3.A=5^3+5^6+5^9+...+5^{102}\)
\(\left(5^3-1\right)A=\left(5^3+5^6+5^9+...+5^{102}\right)-\left(1+5^3+5^6+5^9+...+5^{99}\right)\)
\(124A=5^{102}-1\)
\(A=\frac{5^{102}-1}{124}\)
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\(5^2\div5\times2^3-3^2+7\)
\(=\)\(25\div5\times8-9+7\)
\(=\)\(5\times8-9+7\)
\(=\)\(40-9+7\)
\(=\)\(31+7\)
\(=\)\(38\)
x=3/2-căn bậc hai(33)/2
x=căn bậc hai(33)/2+3/2
HT
1,a,2x=16=24⇒x=4b,3x+1=9x=32x⇒x+1=2x⇒x=1c,23x+2=4x+5=22(x+5)⇒3x+2=2x+10⇒x=8d,32x−1=243=35⇒2x−1=5⇒x=32,a,2225=875<975=3150b,291=(213)7=81927>31257=(55)7=535c,9920=(992)10<(99⋅101)10=9999103,a,128⋅912=216⋅38⋅324=216⋅332=(2⋅32)16=1816b,7520=(3⋅52)20=320⋅540=(320⋅510)⋅530=(32⋅5)10⋅530=4510⋅530