x=3/2-căn bậc hai(33)/2

x=căn bậc hai(33)/2+3/2

HT

1,a,2x=16=24⇒x=4b,3x+1=9x=32x⇒x+1=2x⇒x=1c,23x+2=4x+5=22(x+5)⇒3x+2=2x+10⇒x=8d,32x−1=243=35⇒2x−1=5⇒x=32,a,2225=875<975=3150b,291=(213)7=81927>31257=(55)7=535c,9920=(992)10<(99⋅101)10=9999103,a,128⋅912=216⋅38⋅324=216⋅332=(2⋅32)16=1816b,7520=(3⋅52)20=320⋅540=(320⋅510)⋅530=(32⋅5)10⋅530=4510⋅530

(8486 - 2x) =320.26

8486 - 2x =8320

2x=8486-8320

2x=166

x=166:2 

x=83

(8486-2x) :26=320     <=>  8486-2x=8320      <=>     -2x=-166       <=> x=83

HỌC TỐT!!!

ta có: 2022=2020+2   suy ra  2020x2022=2020x(2020+2) = 2020² +4040

ta có:2021=2020+1    suy ra    2021x2021=(2020+1)x(2020+1)=2020²+2020+2020+1=2020²+4041

Như vậy ta thấy 2020²+4041>2020²+4040

Vậy    2020x2022<2021x2021

DAP AN 1O NHA BAN

16x+40=120

16x=120-40

16x=80

x=80:16

x=5

Vì \(x\in B\left(7\right)\)

\(\Rightarrow\)\(x\in\){ 0 ; 7 ; 14 ; 21 ; 28 ; 35 ; 42 ; 49 ; 56 ; 63 ; 70 ; 77 ; ..... }

mà \(x< 70\)

\(\Rightarrow\)\(x\in\){ 0 ; 7 ; 14 ; 21 ; 28 ; 35 ; 42 ; 49 ; 56 ; 63 ; 70 }

B(7) = { 0; 7; 14; 21; 28; 35; 42; 49; 56; 63; 70; ....}

Mà x<70 nên x ∈ { 0; 7; 14; 21; 28; 35; 42; 49; 56; 63 }

\(A=1+5^3+5^6+...+5^{99}\)

\(5^3.A=5^3+5^6+5^9+...+5^{102}\)

\(\left(5^3-1\right)A=\left(5^3+5^6+5^9+...+5^{102}\right)-\left(1+5^3+5^6+5^9+...+5^{99}\right)\)

\(124A=5^{102}-1\)

\(A=\frac{5^{102}-1}{124}\)

5^{2 :} 5 x 2³ - 3² +7

= 5 x 8 - 9 + 7

= 40 - 9 + 7

= 31 + 7

= 38

\(5^2\div5\times2^3-3^2+7\)

\(=\)\(25\div5\times8-9+7\)

\(=\)\(5\times8-9+7\)

\(=\)\(40-9+7\)

\(=\)\(31+7\)

\(=\)\(38\)