Giups mình nhé mình đang cần gấp
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Có công thức : l a l + l b l > l a + b l
=> l x- 2 l + l x - 3 l
=> l x - 2 l + l 3 - x l
=> l x - 2 l + l 3 - x l \(\ge\)l x - 2 + 3 - x l ( = 1 )
=> Vậy GTNN là 1 khi x \(\ge\)3
=>
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề : \(\frac{x+3}{2010}+\frac{x+2}{2011}-\frac{x+1}{2012}=\frac{x-1}{2014}\)
\(\Leftrightarrow\frac{x+3}{2010}+1+\frac{x+2}{2011}+1-\frac{x+1}{2012}+1=\frac{x-1}{2014}+1\)
\(\Leftrightarrow\frac{x+3+2010}{2010}+\frac{x+2+2011}{2011}-\frac{x+1+2012}{2012}=\frac{x-1+2014}{2014}\)
\(\Leftrightarrow\frac{x+2013}{2010}+\frac{x+2013}{2011}-\frac{x+2013}{2012}=\frac{x+2013}{1014}\)
\(\Leftrightarrow\frac{x+2013}{2010}+\frac{x+2013}{2011}-\frac{x+2013}{2012}-\frac{x+2013}{2014}=0\)
\(\Leftrightarrow\left(x+2013\right)\left(\frac{1}{2010}+\frac{1}{2011}-\frac{1}{2012}-\frac{1}{2014}\right)=0\)
\(\Rightarrow x+2013=0\)( Vì ( \(\frac{1}{2010}+\frac{1}{2011}-\frac{1}{2012}-\frac{1}{2014}\)) \(\ne0\))
\(\Rightarrow x=-2013\)