(x-3)3-(x-3)(x2+3x+9)+9(x+1)2=15
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a/ 1097 x 32 + 1097 x 67 + 1097
= 1097 x ( 32 + 67 +1)
= 1097 x 100
= 10970
b/ 846 x 95 + 3 x 846 + 846 + 846
= 846 x ( 95 + 3 + 1+ 1)
= 846 x 100
= 84600
1097(32+67+1)=1097x100=109700
846 x 95 + 3 x 846 + 846 + 846
846x(95+3+1+1)=846x100=84600
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Nhầm xíu :>>
Đặt \(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{55}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+...+\frac{1}{10\times11}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{2}-\frac{1}{11}\Rightarrow\frac{1}{2}A=\frac{9}{22}\Rightarrow A=\frac{9}{11}\)
Đặt \(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{55}\)
\(\Rightarrow2A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\)
\(\Rightarrow2A=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+...+\frac{1}{10\times11}\)
\(\Rightarrow2A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\)
\(\Rightarrow2A=\frac{1}{2}-\frac{1}{11}\Rightarrow2A=\frac{9}{22}\Rightarrow A=\frac{9}{44}\)
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S=1 + 3 + 5 + ... + 99 + 101
=> S = ( 101 + 1 ) . 51 : 2
=> S = 102 . 51 ; 2
=> S = 5202 : 2
=> S = 2601
Ta có: 1+3+5+...+99+101
Tổng trên là:(1+101).2= 204
Đ/S: 204
k cho mk nha!!!!
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6.7.168 – 14.85.3 + 17.21.2
= 42 . 168 - 42 . 85 + 42 . 17
= 42 . ( 168 - 85 + 17 )
= 42 . 100
= 4200
= 2.3.7.168 - 2.7.85.3 + 17.2.21
= 21.336 - 21.170 + 21.34
= 21.( 336 + 34 - 170 )
= 21.200
= 4200
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\(\left|2x-4\right|=\left|5x+3\right|\)
\(\Rightarrow\orbr{\begin{cases}2x-4=5x+3\\2x-4=-5x+3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-4=5x+3\\2x-5x=-5x-3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-5x=3+4\\2x+5x=-3+4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}-3x=7\\7x=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-7}{3}\\x=\frac{1}{7}\end{cases}}\)
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( 57 - 3 × X ) × 12 - 24 = 47 × 2 - 82
( 57 - 3 × X ) × 12 - 24 = 94 - 82
( 57 - 3 × X ) × 12 - 24 = 12
( 57 - 3 × X ) × 12 = 12 + 24
( 57 - 3 × X ) × 12 = 36
57 - 3 × X = 36 : 12
57 - 3 × X = 3
3 × X = 57 - 3
3 × X = 54
X = 54 : 3
X = 18
( 57 - 3 × X ) × 12 - 24 = 47 × 2 - 82
= ( 57 - 3 × X ) × 12 - 24 = 94 - 82
= ( 57 - 3 × X ) × 12 - 24 = 12
= ( 57 - 3 × X ) × 12 = 12 + 24
= ( 57 - 3 × X ) × 12 = 36
= 57 - 3 × X = 36 : 12
= 57 - 3 × X = 3
= 3 × X = 57 - 3
= 3 × X = 54
X = 54 : 3
X = 18
Ta có: \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+9\left(x+1\right)^2=15\)
⇔ \(x^3-9x^2\)+ 27x − 27 −\(x^3\)+ 27 +\(9x^2\)+ 18x + 9 = 15
⇔ 45x = 6
hay \(x=\frac{2}{15}\)
x = 2/15