\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\left(\frac{3}{7}\right)^2\right)^6\)

\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\)

\(=\left(\frac{3}{7}\right)^{21-12}\)

\(=\left(\frac{3}{7}\right)^9\)

dap so 5 gio

a)4x-3 chia hết cho x-2

4x-8+5 chia hết cho x-2

(4x-8)+5 chia hết cho x-2

4(x-2)+5 chia hết cho x-2 <=> 5 chia hết cho x-2 [vì 4(x-2) luôn chia hết cho x-2]

 x-2 E {1;-1;5;-5}

Nếu x-2=1          Nếu x-2=-1            Nếu x-2=5          Nếu x-2=-5

       x=1+2=3            x=-1+2=1             x=5+2=7             x=-5+2=-3

\(12^8.9^{12}=18^{16}\)

\(\left(3.4\right)^8.3^{24}=\left(2.9\right)^{16}\)

\(3^8.4^8.3^{24}=2^{16}.9^{16}\)

\(3^{32}.2^{16}=2^{16}.3^{32}\)

a) A = 1/2.5 + 1/5.8 + 1/8.11 + 1/11.14 + 1/14.17 + 1/17.20

=> 3A = 1/2 - 1/5 + 1/5 - .... + 1/14 - 1/17 + 1/17 - 1/20

=> 3A = 1/2 - 1/20 = 9/20

=> A = 3/20

b) 2004¹⁰ + 2004⁹ = 2004⁹(1+2004) = 2004⁹ . 2005

2005¹⁰  = 2005⁹  . 2005

Do 2005⁹ > 2004⁹ nên 2004¹⁰ + 2004⁹ < 2005¹⁰

\(\frac{45^{10}\times5^{20}}{75^{15}}=\frac{\left(3^2\times5\right)^{10}\times5^{20}}{\left(5^2\times3\right)^{15}}\)\(=\frac{3^{20}\times5^{10}\times5^{20}}{5^{30}\times3^{15}}\)\(=3^5\)= 243

bạn tự kẻ hình nha!!

Ta có: xOv  = xOy - yOv  = xOy - 90(độ)

          tOy = xOy - xOt = xOy - 90(độ)

Vậy xOv = tOy

Sai thì thui nha cái này mk làm bừa ^^^^