2^3 nhân 2^7
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(A=\frac{x^2-x}{x^2-9}-\frac{1}{x-3}+\frac{1}{x+3}\)
\(=\frac{x\left(x-1\right)}{\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x+3}\)
\(=\frac{x\left(x-1\right)-x-3+x-3}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{x^2+x-6}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{\left(x-2\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)
\(=\frac{x-2}{x-3}\)
\(A=\frac{x^2-x}{x^2-9}-\frac{1}{x-3}+\frac{1}{x+3}\)
\(A=\frac{x^2-x}{x^2-3^2}-\frac{1}{x-3}+\frac{1}{x+3}\)
\(A=\frac{x^2-x}{\left(x-3\right)\left(x+3\right)}-\frac{x+3}{\left(x-3\right)\left(x+3\right)}+\frac{x-3}{\left(x-3\right)\left(x-3\right)}\)
\(A=\frac{x^2-x-\left(x+3\right)+x-3}{\left(x-3\right)\left(x+3\right)}\)
\(A=\frac{x^2-x-x-3+x-3}{\left(x-3\right)\left(x+3\right)}\)
\(A=\frac{x^2-x}{\left(x-3\right)\left(x+3\right)}\)
= 84
HT
ý em là 2/3 x 2/7:))