\(abc+acb=743\)

\(367+376=743\) hoặc \(376+367=743\)

\(k.nha\)

 a=3,b=6,c=7

k cho mk nha mk đang -16

\(abc+acb=743\)

\(367+376=743\)hoặc \(376+367=743\)

\(\Rightarrow a=3\)giữ nguyên

     \(b=6\)hoặc \(b=7\)

     \(c=7\)hoặc \(c=6\)

\(k.nha\)

\(\overline{abc}+\overline{acb}=200.a+11.b+11.c=743\)

\(\Rightarrow a< 4\)

+ Do \(b;c\le9\Rightarrow11.b+11.c\le198\)\(\Rightarrow a>2\)

\(\Rightarrow2< a< 4\Rightarrow a=3\)

\(\Rightarrow200.a+11.b+11.c=200.3+11\left(b+c\right)=743\)

\(\Rightarrow11.\left(b+c\right)=143\Rightarrow b+c=13\)

=> ta có các cặp số

349+394=743

358+385=743

367+376=743

376+367=743

385+358=743

394+349=743

15 x 6 x 4 x 125 x 8

= (15 x 4) x (125 x 8) x 6

= 60 x 1000 x 6

= 60000 x 6

= 360000

15 x6x4x125x8

= (15x4)x6x(125x8)

= 60x6 x 1000

= 360 x 1000

= 360 000

4^{(1+2+3+4+....+2018)}

4^2037171

mk nghĩ tek

hok tốt

4 + 4² + 4³ + .....+ 4²⁰¹⁸

sorry mình bị nhầm đề

theo mk a=3,b=6,c=7

so sánh:

27²⁵ và 16³⁸

A=1+2+3+4+...+2017+2018-2019

A=[(2018-1):1+1]-2019=2018

A= [(2018+1) x 2018 :2 =2037171

A= 2037171 - 2019

A=2035152

hok tốt 

\(A=1+2+...+2017+2018-2019\)

\(A=\frac{\left(2018+1\right).2018}{2}-2019\)

\(A=2035152\)