Nguoi ta dem trung tronh mot ro.Neu dem theo chuc thi vua du,neu dem theo ta(12 qua) thi du 2 qua,neu dem tung 15 qua mot thi du 5.Tinh so trung trong ro,biet so trung chua den 100
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Đặt \(A=\frac{9+\frac{9}{11}+\frac{18}{23}-\frac{27}{37}}{8+\frac{8}{11}+\frac{16}{23}-\frac{24}{37}}-\frac{2+\frac{16}{29}-\frac{24}{13}-\frac{32}{11}}{3+\frac{24}{29}-\frac{36}{13}-\frac{48}{11}}\)\(=\frac{9\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}{8\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}-\frac{2\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}{3\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}\)
\(=\frac{9}{8}-\frac{2}{3}\)(do \(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37};1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\ne0\))
\(=\frac{27}{24}-\frac{16}{24}=\frac{11}{24}.\)
Vậy A = \(\frac{11}{24}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(x - 3)(2x + 6) = 0
=> \(\orbr{\begin{cases}x-3=0\\2x+6=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=3\\2x=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
Vậy ...
(x-3)(2x+6)=0
\(\Leftrightarrow\orbr{\begin{cases}x-3=0\\2x+6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\2x=-6\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=3\\x=-3\end{cases}}}.\)
Vậy x = 3 hoặc x = -3.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=2^1+2^2+2^3+2^4+...+2^{60}\)
\(=2+2^2+2^3+2^2+...+2^{58}+2^{59}+2^{60}\)
\(=2\left(1+2+4\right)+2^4\left(1+2+4\right)+...+2^{58}\left(1+2+4\right)\)
\(=2.7+2^4.7+...+2^{58}.7=7\left(2+2^4+...+2^{58}\right)\)
\(\Rightarrow A⋮7\left(đpcm\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
920 = (32)20 = 340
2713 = (33)13 = 339
Vì 340 > 339
=> 920 > 2713
ta có:920=(32)20=340
2713=(33)13=339
vì 340>339 =>920>2713
HỌC GIỎI NHÁ!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
A,35*34+35*86+65*75+65*45
=35*[34+86]+65*[75+45]
=35*100+65*120
=35*100+65*100+65*20
=[35+65]*100+65*20
=10000+1300=11300
số trứng trong rổ là 50
Cac ban lam day du giup minh nha!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!