ko bít

CHO TEN ROI NOI

ngọc anh ạ

=0

k mik nha

bài này dễ, chú ý số cuối bằng 0.Vậy nên kết quả bằng 0

X= 10000000

Ghi lời giải giùm mình được không?

(x-1)(x^2+3x-2-x^2-x-1)=(x-1)(2x-3)=0=> x=1 hoăc x=3/2

(x-1)(x²+3x-2)-(x³-1)=0

<=>(x-1)(x²+3x-2)-(x-1)(x²+x+1)=0

<=>(x-1)(x²+3x-2-(x²+x+1))=0

<=>(x-1)(x²+3x-2-x²-x-1)=0

<=>(x-1)(2x-3)=0

<=>x-1=0 hay 2x-3=0

<=>x=1 hay x=\(\frac{3}{2}\)

• <=>(x-1)(x²+3x-2) - (x-1)(x²+x+1)=0
• <=>(x-1)(x²+3x-2-x²-x-1)=0
• <=>(x-1)(2x-3)=0
• <=>x-1=0 hoặc 2x-3=0
• <=>x=1 hoặc x=3/2

VẬY S=1;3/2                :)))))))))))))))))))))))))

\(\frac{x-2}{2012}+\frac{x-3}{2011}+\frac{x-4}{2010}+\frac{x-2029}{5}=0\)

\(\Leftrightarrow\frac{x-2}{2012}-1+\frac{x-3}{2011}-1+\frac{x-4}{2010}-1+\frac{x-2029}{5}+3=0\)

\(\Leftrightarrow\frac{x-2014}{2012}+\frac{x-2014}{2011}+\frac{x-2014}{2010}+\frac{x-2014}{5}=0\)

\(\Leftrightarrow\left(x-2014\right)\left(\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}+\frac{1}{5}\right)=0\)

\(\Leftrightarrow x-2014=0\).Do \(\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}+\frac{1}{5}\ne0\)

\(\Leftrightarrow x=2014\)

sorry toi chua hoc

\(\frac{y-1}{y-2}-\frac{5}{y+2}=\frac{12}{y^2-4}+1\)

 \(\frac{\left(y-1\right)\left(y+2\right)}{y^2-4}-\frac{5\left(y-2\right)}{y^2-4}=\frac{12}{y^2-4}+\frac{y^2-4}{y^2-4}\)

\(\frac{y^2+y-2-5y+10}{y^2-4}=\frac{y^2+8}{y^2-4}\)

\(y^2-4y-8=y^2+8\)

 \(y^2-4y-8-y^2-8=0\)

 \(-4y-16=0\)

\(\Rightarrow y=-4\)

            Vậy y=-4

\(\Leftrightarrow\frac{y-1}{y-2}-\frac{5}{y+2}=\frac{12}{\left(y-2\right)\left(y+2\right)}+1\)

\(\Leftrightarrow\frac{\left(y-1\right)\left(y+2\right)-5\left(y-2\right)-12+1\left(y-2\right)\left(y+2\right)}{\left(y-2\right)\left(y+2\right)}=0\)

\(\Leftrightarrow\frac{y^2+2y-y-2-5y+10-12+y^2+2y-2y-4}{\left(y-2\right)\left(y+2\right)}\)

Rồi bạn làm tiếp nha