\(\sqrt{36}+\sqrt{10000}-\sqrt{4}+\sqrt{25}-\sqrt{36}+\sqrt{49}-\sqrt{10000000000}\)

\(=6+100-2+5-6+7-100000\)

\(\text{=-99890}\)

=6+100-2+5-6+7-100000

=-99890

Mình có việc bận nên bạn tự làm tiếp nha, mk chỉ ghi kết quả thôi.

Ta có:\(\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=\frac{x+y+z}{a+b+c}\)\(\Rightarrow\frac{x^2}{a^2}=\frac{y^2}{b^2}=\frac{z^2}{c^2}=\frac{\left(x+y+z\right)^2}{\left(a+b+c\right)^2}=\frac{x^2+y^2+z^2}{a^2+b^2+c^2}\)

\(\Rightarrow\frac{\left(x+y+z\right)^2}{\left(a+b+c\right)^2}=\frac{x^2+y^2+z^2}{a^2+b^2+c^2}=\frac{\left(x+y+z\right)^2}{1^2}=\frac{x^2+y^2+z^2}{1}\)

\(\Rightarrow\left(x+y+z\right)^2=x^2+y^2+z^2\)

Kết quả là -1

\(A=\frac{10x+15}{5x+1}=\frac{5x+1+5x+1+13}{5x+1}=\frac{5x+1}{5x+1}+\frac{5x+1}{5x+1}+\frac{13}{5x+1}=1+1+\frac{13}{5x+1}\)

Để \(A\in Z\Leftrightarrow1+1+\frac{13}{5x+1}\in Z\)

Mà \(1\in Z\Leftrightarrow\frac{13}{5x+1}\in Z\)

\(\Leftrightarrow5x+1\inƯ_{13}=\left\{-13;-1;1;13\right\}\)

\(\Leftrightarrow x=\left\{-\frac{14}{5};-\frac{2}{5};0;\frac{12}{5}\right\}\).

Mà \(x\)nguyên => x={0}

        \(2.|x+183|-2.5^2=100.\)

\(\Leftrightarrow2.|x+183|-50=100\)

\(\Leftrightarrow2.|x+183|=50\)

\(\Leftrightarrow|x+183|=25\)

\(\Leftrightarrow\orbr{\begin{cases}x+183=25\\x+183=-25\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-158\\x=-208\end{cases}}\)