(3 : 4 - x)³ = -8

=> (3 : 4 - x)³ = (-2)³

=> 3 : 4 - x = 2

=> \(\frac{3}{4}\) - x = 2

=>  = \(-\frac{5}{4}\)

\(\left(3:4-x\right)^3=-8\)

\(\Leftrightarrow\left(3:4-x\right)^3=\left(-2\right)^3\)

\(\Leftrightarrow3:4-x=-2\)

\(\Leftrightarrow4-x=-1,5\)

\(\Leftrightarrow x=5,5\)

Đúng thì cho xin cái

5^x + 5 ^x+1 = 5^x + 5^x . 5 = 5^x .(1+5) = 725

=> 5^x = 725 : 6 = \(\frac{725}{6}\)

mà 5^x \(\in\)Z

=> x ko có giá trị

5^x+5^x+5=725

5^x.(1+5)=725

5^x=725:6(vo li)

=>xthuoc rong

        3^x-2 -24 . 3² = 3² . 3

<=> 3^x-2 -216 = 27

<=> 3^x-2 =243

<=> 3^x-2 = 3⁵

<=> x-2 = 5

<=> x = 7

\(3^{x-2}-24\cdot3^2=3^2\cdot3\)

\(3^{x-2}-24\cdot9=9\cdot3\)

\(3^{x-2}-216=27\)

\(3^{x-2}=27+216=243\)

\(\Rightarrow3^{x-2}=3^5\)

\(\Rightarrow x-2=5\)

\(\Rightarrow x=5+2=7\)

tk mk nha. ~CHÚC BẠN HỌC TỐT~

Đề bài là gì thế?

đề bài là tính

4^x+4 : 4² = 16^x

=> 4^x+2 = 4^2x

=> x+2 = 2x

=> x = 2  

4^x+4 : 4² = 16^x

=> 4^x+2 = 4^2x

=> x+2 = 2x

=> x = 2  

a) \(2^n\times128=2^{10}\)

\(\Rightarrow2^n\times2^7=2^{10}\)

\(\Rightarrow2^n=2^{10}\div2^7\)

\(\Rightarrow2^n=2^3\)

\(\Rightarrow n=3\)

b) \(7^2\times8+7^2\times5=7^2\times\left(8+5\right)=7^2\times13=49\times13=637\)

c) \(30-\left[18-\left(10-9\right)^{100}\right]=30-\left(18-1^{100}\right)=30-\left(18-1\right)=30-17=13\)

2ⁿ.128 = 2¹⁰

=> 2ⁿ.2⁷ = 2¹⁰

=> 2^{n + 7} = 2¹⁰

=> n + 7 = 10

=> n = 3

vậy_

a) Nếu \(\frac{1}{2}x\ge0\Rightarrow x\ge0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow\frac{1}{2}x=3-2x\Rightarrow\frac{5}{2}x=3\Rightarrow x=\frac{6}{5}\) (nhận)

   Nếu \(\frac{1}{2}x< 0\Rightarrow x< 0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow-\frac{1}{2}x=3-2x\Rightarrow\frac{3}{2}x=3\Rightarrow x=2\) (loại)

Vậy x = 6/5

b) Nếu \(x-1\ge0\Rightarrow x\ge1\) thì \(\left|x-1\right|=3x+2\Rightarrow x-1=3x+2\Rightarrow-2x=3\Rightarrow x=\frac{-2}{3}\) (loại)

Nếu \(x-1< 0\Rightarrow x< 1\) thì \(\left|x-1\right|=3x+2\Rightarrow-\left(x-1\right)=3x+2\Rightarrow-x+1=3x+2\Rightarrow-4x=1\Rightarrow x=\frac{-1}{4}\) (nhận)

Vậy x = -1/4