K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

24 tháng 12 2019

chịu but Merry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry ChristmasMerry Christmas

Only 10 days left until Christmas !! Have prepared to go into the warm Christmas sweater, hang socks on the chimney (if any) and harmoniously dance and dance to the jubilant Christmas rhythms. So when people reunite together this Christmas, we will hug each other tightly, smile and say the first sentence? Of course it will be Merry Christmas. As a global citizen welcoming a global holiday, we must be able to say Merry Christmas in different languages ​​to congratulate our friends all over the world in order to be right. is that right? For example, Christmas greetings in French, German, Spanish, Chinese, Japanese and many other languages, etc. EF teams around the world sit down and bring the You have 15 Christmas wishes in their native language. Please accept this challenge and prace speaking Merry Christmas in different languages ​​properly!

24 tháng 12 2019

thank you and you too

Merry Christmas

nhìn mà mù mắt , rắc rối vl

29 tháng 12 2019

\(\frac{x^2-36}{2x+10}.\frac{3}{6-x}\)

\(=\frac{\left(x^2-36\right).3}{\left(2x+10\right)\left(6-x\right)}\)

\(=\frac{3\left(x+6\right)\left(x-6\right)}{\left(2x+10\right)\left(6-x\right)}\)

\(=-\frac{3\left(x+6\right)\left(x-6\right)}{2\left(x+5\right)\left(x-6\right)}\)

\(=-\frac{3\left(x+6\right)}{2\left(x+5\right)}\)

25 tháng 12 2019

\(VT=a-\frac{ab^2}{b^2+1}+b-\frac{bc^2}{c^2+1}+c-\frac{ca^2}{a^2+1}\)

\(=3-\left(\frac{ab^2}{b^2+1}+\frac{bc^2}{c^2+1}+\frac{ca^2}{a^2+1}\right)\)

Áp dụng BCS:

\(\frac{ab^2}{b^2+1}\le\frac{ab^2}{2b}=\frac{ab}{2}\)

\(\frac{bc^2}{c^2+1}\le\frac{bc^2}{2c}=\frac{bc}{2}\)

\(\frac{ca^2}{a^2+1}\le\frac{ca^2}{2a}=\frac{ca}{2}\)

\(\Rightarrow3-\left(\frac{ab^2}{b^2+1}+\frac{bc^2}{c^2+1}+\frac{ca^2}{a^2+1}\right)\ge3-\frac{ab+bc+ca}{2}\)

Ta có BĐT phụ:

\(\left(a+b+c\right)^2\ge3\left(ab+bc+ca\right)\)

\(\Rightarrow ab+bc+ca\le3\)(vì a+b+c=3)

\(\Rightarrow\frac{ab+bc+ca}{2}\le\frac{3}{2}\)

\(\Rightarrow3-\frac{ab+bc+ca}{2}\ge\frac{3}{2}\)

Vậy \(VT=a-\frac{a}{1+b^2}+\frac{b}{1+c^2}+\frac{c}{1+a^2}\ge\frac{3}{2}\)

(Dấu "="\(\Leftrightarrow a=b=c=1\))

27 tháng 12 2019

https://olm.vn/hoi-dap/detail/227071860547.html