\(3x+1+\left|x-3\right|=22\Leftrightarrow\left|x-3\right|=21-3x\)

ĐK : \(21-3x\ge0\Leftrightarrow-3x\ge-21\Leftrightarrow x\le7\)

TH1 : \(x-3=21-3x\Leftrightarrow-4x=-24\Leftrightarrow x=6\)( tm )

TH2 : \(x-3=3x-21\Leftrightarrow2x=18\Leftrightarrow x=9\)( ktm ) 

2. ( x-3 ) + 3. (x+5) > 16

x = 7/5

-1/10+2/5.x+7/20=1/10

-1/10+2/5.x=-1/4

2/5.x=-3/20

x=-3/8

\(-\frac{1}{10}+\frac{2}{5}x+\frac{7}{20}=\frac{1}{10}\)

\(-\frac{1}{10}+\frac{2}{5}x=\frac{1}{10}-\frac{7}{20}\)

\(\frac{2}{5}x=\frac{-1}{4}+\frac{1}{10}\)

\(\frac{2}{5}x=\frac{-3}{20}\)

\(x=\frac{-3}{20}:\frac{2}{5}\)

\(x=\frac{-3}{8}\)

Vậy x = \(\frac{-3}{8}\)

\(3\left(5x+\frac{2}{3}\right)^2=\frac{4}{3}\)

\(\left(5x+\frac{2}{3}\right)^2=\frac{4}{9}\)

\(25x^2+2.5x.\frac{2}{3}+\frac{4}{9}=\frac{4}{9}\)

\(25x^2\frac{20}{3}x=0\)

\(x\left(25x+\frac{20}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\25x+\frac{20}{3}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{-4}{15}\end{cases}}\)

\(\left(13\frac{9}{11}\div\frac{38}{49}-5\frac{2}{11}\div\frac{38}{49}\right)\div\left(\frac{49}{38}.\frac{5}{11}\right)\)

\(=\left(\frac{152}{11}\div\frac{38}{49}-\frac{57}{11}\div\frac{38}{49}\right)\div\frac{245}{418}\)

\(=\left(\frac{196}{11}-\frac{147}{22}\right)\div\frac{245}{418}\)

\(=\frac{245}{22}\div\frac{245}{418}\)

\(=19\)

Đề bài thiếu à 

tìm n nguyên để biểu thức nguyên ? 

\(\frac{5n+1}{2n-3}=\frac{10n+2}{2n-3}=\frac{5\left(2n-3\right)+17}{2n-3}=\frac{17}{2n-3}\)

\(\Rightarrow2n-3\inƯ\left(17\right)=\left\{\pm1;\pm17\right\}\)