1+2+3+4+...+2020=?
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a) = (32)2 x 37
= 34 x 37
= 311
b) 512 x 59
= 29 x 59
= (2x5)9
= 109
c) 210 x 255
= 210 x ( 52 )5
= 210 x 510
=(2x5)10
= 1010
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\(a,\sqrt{3+2\sqrt{2}}\)\(+\sqrt{6-4\sqrt{2}}\)
\(=\sqrt{\left(\sqrt{2}+1\right)^2}\)\(+\sqrt{\left(2-\sqrt{2}\right)^2}\)
\(=\sqrt{2}\)\(+1+2-\sqrt{2}\)
\(=\left(\sqrt{2}-\sqrt{2}\right)+1+2\)
\(=0+1+2=3\)
a) \(\sqrt{3+2\sqrt{2}}\)+\(\sqrt{6-4\sqrt{2}}\)
=\(\sqrt{\left(\sqrt{2}+1\right)^2}\)+\(\sqrt{\left(2-\sqrt{2}\right)^2}\)=\(\sqrt{2} +1+2-\sqrt{2}\)=3
b)\(\left(\sqrt{5}-2\sqrt{6}+\sqrt{2}\right)\sqrt{3}\)
=\((\sqrt{\left(\sqrt{3})-\sqrt{2}\right)^2}+\sqrt{2})\sqrt{3}\)
=\(\left(\sqrt{3}-\sqrt{2}+\sqrt{2}\right)\sqrt{3}\)
=\(\sqrt{3}.\sqrt{3}=3\)
S=1+2+3+4+5+....+2020S=1+2+3+4+5+....+2020
Số các số hạng là:
(2020−1):1+1=2020(2020−1):1+1=2020 số.
Vậy S=(2020+1).20202=2041210