bài 1 cho hàm số y=f(x)=ax2+bx+c
cho biết f(0) =2010
f(1)=2011
f(-1)=2012
Tính f(2)
bài 2cho x,y,z khác 0 thoả mãn \(\frac{y+z-x}{x}=\frac{x+z-y}{y}=\frac{x+y-z}{z}\)
Hãy tính B=\(\left(1+\frac{x}{y}\right).\left(1+\frac{y}{z}\right).\left(1+\frac{z}{x}\right)\)
bài 1,sai đề
bài 2:\(\frac{y+z-x}{x}=\frac{x+z-y}{y}=\frac{x+y-z}{z}=\frac{y+z-x+x+z-y+x+y-z}{z+y+x}=\frac{x+y+z}{x+y+z}=1\)
\(\Rightarrow y+z-x=x\Rightarrow y+z=2x\)
\(x+z-y=y\Rightarrow x+z=2y\)
\(x+y-z=z\Rightarrow x+y=2z\)
\(\left(1+\frac{x}{y}\right)\left(1+\frac{y}{z}\right)\left(1+\frac{z}{x}\right)=\frac{x+y}{y}.\frac{y+z}{z}.\frac{x+z}{x}=\frac{\left(x+y\right)\left(y+z\right)\left(x+z\right)}{xyz}=\frac{2z.2y.2x}{xyz}=2.2.2=8\)
đùa nhau à