Cho A = 20213 và B = 2020.2021.2022 Không tính cụ thể các giá trị của A và B, hãy so sánh A và B.
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
=100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000667685854796068675796859584848744473245789786447321246787000000000000000000000000000000000000000000000
=1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000006676858547960686757968595848487444732457897864432124678700000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 vé báo cáo
@congtybaocao
![](https://rs.olm.vn/images/avt/0.png?1311)
Answer:
Chiều dài
\(48:\left(5-3\right)\times5=120m\)
Chiều rộng
\(120-48=72m\)
Diện tích
\(120\times72=8640m^2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A < B
HT
Đặt \(2021=a\), khi đó \(A=a^3\)và \(B=a\left(a-1\right)\left(a+1\right)\)
Ta có: \(B=a\left(a-1\right)\left(a+1\right)=\left(a^2-a\right)\left(a+1\right)=a^3+a^2-a^2-a=a^3-a\)
Vì \(a>0\)nên hiển nhiên ta có \(B=a^3-a< a^3=A\)
Vậy \(A>B\)