\((x - 1/2)^3 = 1/27\)
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\(b,\left(2\chi-7\right)^{4-1}=4^{2\times5}\)\(a,3\times2^{\chi-7}=17\)
a) \(3.2^x-7=17\)
\(3\cdot2^x=24\)
\(2^x=8=2^3\)
=> x = 3
b) \(\left(2x-7\right)^4-1=4^2\cdot5\)
\(\left(2x-7\right)^4-1=80\)
\(\left(2x-7\right)^4=81=\left(\pm3\right)^4\)
+) 2x - 7 = 3
2x = 10
x = 5
+) 2x - 7 = -3
2x = 4
x = 2
Vậy,...........
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\(7^x.7^2+2.\frac{7^x}{7}=345\)
\(343.7^x+2.7^x=7.345\)
\(345.7^x=7.345\Rightarrow7^x=7\Rightarrow x=1\)
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a) \(2^x\cdot2^2-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x=32=2^5\)
=> x = 5
b) \(\left(2x+1\right)^3=7^3\)
=> 2x +1 = 7
=> 2x = 6
=> x = 3
Vậy,..........
a. 2x+2 - 2x = 96
2x . 22 - 2x = 96
2x. (22 - 1) = 96
2x = 96 : 3
2x = 32
2x = 25
x = 5
b. (2x + 1)3 = 343
(2x + 1)3 = 73
2x + 1 = 7
2x = 7 - 1
x = 6 : 2
x = 3
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( a - b + c ) - ( a - b - c ) + ( -a - b + c )
= a - b + c - a + b + c - a - b + c
= ( a - a - a ) - ( b - b + b ) + ( c + c + c )
= -a - b + 3c
\(\left(a-b+c\right)-\left(a-b-c\right)+\left(-a-b+c\right)\)
\(=a-b+c-a+b+c-a-b+c\)
\(=\left(a-a-a\right)-\left(b-b+b\right)+\left(c+c+c\right)\)
\(=-a-b+3c\)
\(\left(\frac{x-1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Rightarrow\frac{x-1}{2}=\frac{1}{3}\)
=> 3x - 3 = 2
=> 3x = 5
=> x = 5/3
Vậy,.........
(x-\(\frac{1}{2}\))3=\(\frac{1}{27}\)
<=>x-\(\frac{1}{2}\)=\(\frac{1}{3}\)
<=>x=\(\frac{5}{6}\)