\(\left(\frac{x-1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)

\(\Rightarrow\frac{x-1}{2}=\frac{1}{3}\)

=> 3x - 3 = 2

=> 3x = 5

=> x = 5/3

Vậy,.........

(x-\(\frac{1}{2}\))³=\(\frac{1}{27}\)

<=>x-\(\frac{1}{2}\)=\(\frac{1}{3}\)

<=>x=\(\frac{5}{6}\)

20082009.20092008-20082008.20092009 = 10000

bằng 0

\(b,\left(2\chi-7\right)^{4-1}=4^{2\times5}\)\(a,3\times2^{\chi-7}=17\)

a) \(3.2^x-7=17\)

\(3\cdot2^x=24\)

\(2^x=8=2^3\)

=> x = 3

b) \(\left(2x-7\right)^4-1=4^2\cdot5\)

\(\left(2x-7\right)^4-1=80\)

\(\left(2x-7\right)^4=81=\left(\pm3\right)^4\)

+) 2x - 7 = 3

2x = 10

x = 5

+) 2x - 7 = -3

2x = 4

x = 2

Vậy,...........

\(7^x.7^2+2.\frac{7^x}{7}=345\)

\(343.7^x+2.7^x=7.345\)

\(345.7^x=7.345\Rightarrow7^x=7\Rightarrow x=1\)

ƯC(-15,20)=1,-1,5,-5,

a) \(2^x\cdot2^2-2^x=96\)

\(2^x\cdot\left(4-1\right)=96\)

\(2^x=32=2^5\)

=> x = 5

b) \(\left(2x+1\right)^3=7^3\)

=> 2x +1 = 7

=> 2x = 6

=> x = 3

Vậy,..........

a. 2^x+2 - 2^x = 96

2^x . 2² - 2^x  = 96

2^x. (2² - 1)  = 96

2^x                = 96 : 3

2^x                = 32

2^x                = 2⁵

x                  = 5

b. (2x + 1)³ = 343

(2x + 1)³     = 7³

2x + 1         = 7

2x               = 7 - 1

x                 = 6 : 2

x                 = 3

( a - b + c ) - ( a - b - c ) + ( -a - b + c )

= a - b + c - a + b + c - a - b + c

= ( a - a - a ) - ( b - b + b ) + ( c + c + c )

= -a - b + 3c

\(\left(a-b+c\right)-\left(a-b-c\right)+\left(-a-b+c\right)\)

\(=a-b+c-a+b+c-a-b+c\)

\(=\left(a-a-a\right)-\left(b-b+b\right)+\left(c+c+c\right)\)

\(=-a-b+3c\)