tim xa)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)giup mk nha moi...
Đọc tiếp
tim x
a)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)
e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)
f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)
g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)
h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
giup mk nha moi nguoi
