\(3x^2-5x-2\)

\(=3x^2+x-6x-2\)

\(=x\left(3x+1\right)-2\left(3x+1\right)\)

\(=\left(x-2\right)\left(3x+1\right)\)

3x² - 5x - 2

= 3x² + x - 6x - 2

= x(3x + 1) - 2(3x + 1)

= (3x + 1)(x - 2)

Ta có bđt:\(a^2-b^2=\left(a+b\right)\cdot\left(a-b\right)\)

Áp dụng ta có: Đề bài sẽ bằng:0 \(\left(4n+3-5\right)\cdot\left(4n+3+5\right)\)\(=\left(4n-2\right)\left(4n+8\right)⋮8\)vì\(4n-2⋮2,4n+8⋮4\)

(4n+3)^2-25

=(4n+3)^2-5^2

=(4n+3+5)(4n+3-5)

=(4n+8)(4n-8)

=[4(n+2)][2(n-4)]

=8(2+n)(n-4)luôn chia hết cho 8 

Vậy...

我不知道你是否理解

lây X ;2 là ra nha bạn

\(x+\frac{22}{33}=\frac{27}{33}\)

\(x=\frac{27}{33}-\frac{22}{33}\)

\(x=\frac{5}{33}\)

x=\(\frac{9}{11}\)- \(\frac{2}{3}\)

x= \(\frac{27}{33}\)-\(\frac{22}{33}\)

x=\(\frac{5}{33}\)

\(A=\left(\frac{3}{5}-0.435+\frac{1}{200}\right)\div\frac{\left(-0.04\right)}{30.75}+\frac{1}{12}+3\frac{1}{6}\)

\(A=\left(\frac{3}{5}-\frac{87}{200}+\frac{1}{200}\right)\div\frac{-4}{3075}+\frac{1}{12}+\frac{19}{6}\)

\(A=\left(\frac{120}{200}-\frac{87}{200}+\frac{1}{200}\right)\div\frac{-4}{3075}+\frac{1}{12}+\frac{19}{6}\)

\(A=\frac{34}{200}×\frac{3075}{-4}+\frac{1}{12}+\frac{19}{6}\)

\(A=\frac{-2091}{16}+\frac{1}{12}+\frac{19}{6}\)

\(A=\frac{-6273}{48}+\frac{4}{48}+\frac{152}{48}\)

\(A=\frac{-6117}{48}=\frac{-2039}{16}\)

Cbht

ban oi phan tat ca ma