Chứng minh rằng:a) P = \(\frac{12}{1.4.7}\)+\(\frac{12}{4.7.10}\)+\(\frac{12}{7.10.13}\)+...+\(\frac{12}{54.57.60}\)<\(\frac{1}{2}\)b) S =...
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Chứng minh rằng:
a) P = \(\frac{12}{1.4.7}\)+\(\frac{12}{4.7.10}\)+\(\frac{12}{7.10.13}\)+...+\(\frac{12}{54.57.60}\)<\(\frac{1}{2}\)
b) S = 1+\(\frac{1}{2^2}\)+\(\frac{1}{3^2}\)+\(\frac{1}{4^2}\)+...+\(\frac{1}{100^2}\)<2
P = 2*[ 6/(1*4*7) + 6/(4*7*10) + ... + 6/(54*57*60) ]
= 2*[ 1/(1*4) - 1/(4*7) + 1/(4*7) - 1/(7*10) + ... + 1/(54*57) -1/(57*60) ]
= 2*[ 1/(1*4) - 1/(57*60) ]
= 2* (427/1710)
= 427/855 <1/2
S = 1+ 1/2^2 + 1/3^2 +... + 1/100^2
1/2^2 < 1/(1*2)
1/3^2 < 1/(2*3)
...
1/100^2 < 1/(99*100)
==> 1/2^2 +1/3^2 +.., +1/100^2 < 1/(1*2) + 1/(2*3) + ... + 1/(99*100) = 1 -1/2 +1/2 - 1/3 +1/3 -1/4 +... - 1/100
=1 - 1/100 <1
==> 1/2^2 + 1/3^2 +... + 1/100^2 < 1
==> 1 + 1/2^2 + 1/3^2 +... +1/100^2 <2