Thu gọn các biều thức.
-(a-b-c)+(-a+b-c)-(-a-b+c)
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Ta có:
9 + x + y + 4 chia hết cho 9
=13 + x +y chia hết cho 9
như vậy ta có thể tìm được các số:
9xy4=9504
=9594
=9414
=9324
=9144
=9954
=9234
=.....
để 9xy4 chia hết cho 9 => 9+x+y+4 chia hết cho 9
=> 13+x+y chia hết cho 9
Mà số lớn nhất mà x và y đạt đc là 9 => x+y lớn hơn hoặc bằng 0 bé hơn hoặc bằng 18
=> 13+x+y lớn hoặc bằng o bé hơn hoặc bằng 31 (18+13)
=> 13 +x+y thuộc ( 18;27)
=> x+y =5 hoặc 14
=> x+y = 2+3=3+2=1+4=4+1
hoặc x+y=7+7=6+8=8+6=5+9=9+5
=> x thuộc (2;3;1;4;7;6;8;5;9)
và y thuộc (3;2;4;1;7;8;6;9;5)
(Mình ko có ngoặc nhọn nên viết ngoặc tròn nhé)
\((\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}).120+y:\frac{1}{3}=-4\)
Ta có: \(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\)
\(=\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\)
\(=\frac{1}{24}-\frac{1}{30}\)
\(=\frac{1}{120}\)
Thay vào ta có: \(\frac{1}{120}.120+y:\frac{1}{3}=-4\)
\(\implies 1+y:\frac{1}{3}=-4\)
\(\implies y:\frac{1}{3}=-5\)
\(\implies y=-5.\frac{1}{3}\)
\(\implies y=\frac{-5}{3}\). Vậy \(y=\frac{-5}{3}\)
~ Học tốt a~
\(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+y:\frac{1}{3}=-4\)
\(\Rightarrow\left(\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\right).120+y:\frac{1}{3}=-4\)
\(\Rightarrow\left(\frac{1}{24}-\frac{1}{30}\right).120+y:\frac{1}{3}=-4\)
\(\Rightarrow\frac{1}{120}.120+y:\frac{1}{3}=-4\)
\(\Rightarrow1+y:\frac{1}{3}=-4\)
\(\Rightarrow y:\frac{1}{3}=-4-1\)
\(\Rightarrow y:\frac{1}{3}=-5\)
\(\Rightarrow y=-5.\frac{1}{3}\)
\(\Rightarrow y=\frac{-5}{3}\)
Vậy \(y=\frac{-5}{3}\)
_Chúc bạn học tốt_
\(a) \frac{4}{5}.x=\frac{8}{35}\)
\(\implies x= \frac{8}{35}:\frac{4}{5}\)
\(\implies x=\frac{8}{35}.\frac{5}{4}\)
\(\implies x=\frac{2}{7}\). Vậy \(x=\frac{2}{7}\)
\(b) \frac{3}{5}x-\frac{1}{2}=\frac{1}{7}\)
\(\implies \frac{3}{5}x=\frac{1}{7}+\frac{1}{2}\)
\(\implies \frac{3}{5}x=\frac{9}{14}\)
\(\implies x=\frac{9}{14}:\frac{3}{5}\)
\(\implies x=\frac{9}{14}.\frac{5}{3} \)
\(\implies x=\frac{15}{14}\). Vậy \(x=\frac{15}{14}\)
\(c) x-25\% x=0,5\)
\(\implies 75\% x=0,5\)
\(\implies \frac{3}{4}x=\frac{1}{2}\)
\(\implies x=\frac{1}{2}:\frac{3}{4}\)
\(\implies x=\frac{1}{2}.\frac{4}{3}\)
\(\implies x=\frac{2}{3}\). Vậy \(x=\frac{2}{3}\)
\(d) (\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}).120+x:\frac{1}{3}=-4\)
Có: \(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\)
\(=\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\)
\(=\frac{1}{24}-\frac{1}{30}\)
\(=\frac{1}{120}\)
Thay vào ta có: \(\frac{1}{120}.120+x:\frac{1}{3}=-4\)
\(\implies 1+x:\frac{1}{3}=-4\)
\(\implies x:\frac{1}{3}=-5\)
\(\implies x=-5.\frac{1}{3}\)
\(\implies x=\frac{-5}{3}\). Vậy \(x=\frac{-5}{3}\)
~ Hok tốt a~
\(\frac{4}{5}.x=\frac{8}{35}\) \(\frac{3}{5}x-\frac{1}{2}=\frac{1}{7}\)
\(x=\frac{8}{35}:\frac{4}{5}\) \(\frac{3}{5}x=\frac{1}{7}+\frac{1}{2}\)
\(x=\frac{8}{35}.\frac{5}{4}\) \(\frac{3}{5}x=\frac{9}{14}\)
\(x=\frac{2}{7}\) \(x=\frac{9}{14}:\frac{3}{5}\)
Vậy \(x=\frac{2}{7}\) \(x=\frac{9}{14}.\frac{5}{3}\)
\(x-25\%x=0.5\) \(x=\frac{15}{14}\)
\(x-\frac{1}{4}x=\frac{1}{2}\) Vậy \(x=\frac{15}{14}\)
\(x\left(1-\frac{1}{4}\right)=\frac{1}{2}\) \(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+x:\frac{1}{3}=-4\)
\(x=\frac{1}{2}:\frac{3}{4}\) \(\left(\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\right).120+x:\frac{1}{3}=-4\) \(x=\frac{2}{3}\) \(\left(\frac{1}{24}-\frac{1}{30}\right).120+x:\frac{1}{3}=-4\)
Vậy \(x=\frac{2}{3}\) \(\frac{1}{120}.120+x:\frac{1}{3}=-4\)
\(1+x:\frac{1}{3}=-4\)
\(x:\frac{1}{3}=\left(-4\right)-1\)
\(x:\frac{1}{3}=-5\)
\(x=\left(-5\right).\frac{1}{3}\)
\(x=-\frac{5}{3}\)
Vậy \(x=-\frac{5}{3}\)
1 . a) 36.23 + 62.23 + 46 = 36.23 + 62.23 + 46.2
= 23 . ( 36 + 62 + 2 )
= 23 . 100
= 2300
2 : TÌm x :
a . 47 . x + 213 = 3.7.3.7
47. x + 213 = 441
47 . x = 441 - 213
47 . x = 228
x = 228 : 47
x = 4,85
b ) 83 + 519 . x = 66.100 + 22
83 + 519 . x = 6600 + 22
83 + 519 . x = 6622
519 . x = 6622 - 83
519 . x = 6539
x = 6539 : 519
x = 12,599
Bài 1:
a. 36.23+62.23+46
= (36+62).23+46
= 98.23 +46
= 2254 + 46
= 2300
Bài 2:
a. 47. x + 213 = 3.7.3.7
47. x + 213 = 441
47. x = 441 - 213
47 . x = 228
x = 228 : 47
Vậy: x = \(\frac{228}{47}\)
b. 83 + 519.x = 66.100 + 22
83 + 519.x = 6600 + 22
83 + 519.x = 6622
519.x = 6622 - 83
519.x = 6539
x = 6539 : 519
Vậy: x = \(\frac{6539}{519}\)
Các số là : 8 ; 16 ; 20 ; 27 ; 60 ; 64 ; 81 ; 90 ; 100 ?
B=\(\left[\left(\frac{1}{3}+\frac{1}{4}\right)x\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{12}x\frac{12}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\frac{5}{4}-\frac{1}{4}+2012\)
B=1+2012
B=2013
\(B=[\left(\frac{1}{3}+\frac{1}{4}\right)\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{12}\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=1:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=\frac{5}{4}-\frac{1}{4}+2012\)
\(B=1+2012\)
\(B=2013\)
\(-\left(a-b-c\right)+\left(-a+b-c\right)-\left(-a-b+c\right)\)
\(=-a+b+c-a+b-c+a+b-c\)
\(=-a+3b-c\)
\(-\left(a-b-c\right)+\left(-a+b-c\right)-\left(-a-b+c\right)\)
\(=-a+b+c-a+b+c+a+b-c\)
\(=\left(-a-a+a\right)+\left(b+b+b\right)+\left(c+c-c\right)\)
\(=-a+3b+c\)