\(2575+37-2576-29\)

\(=2612-2576-29\)

\(=36-29=7\)'

\(35+35+36+37-14-15-16-17\)

\(=70+\left(36-16\right)+\left(37-17\right)-14-15\)

\(=70+20+20-14-15\)

\(=90+6-15\)

\(=96-15=81\)

\(13\cdot\left(-12\right)+87.\left(-12\right)\)

\(=\left(-12\right)\cdot\left(13+87\right)\)

\(=\left(-12\right)\cdot100=-1200\)

\(26\cdot17+17\cdot74\)

\(=\left(26+74\right)\cdot17\)

\(=100\cdot17=1700\)

\(25\cdot\left(-18\right)+25\left(-82\right)\)

\(=25\cdot\left[\left(-18\right)+\left(-82\right)\right]\)

\(=25\cdot\left(-100\right)=\left(-2500\right)\)

\(25+37-48-25-37\)

\(=\left(25-25\right)+\left(37-37\right)-48\)

\(=0+0-48\)

\(=0-48=\left(-48\right)\)

\(\left(-16\right)+24+16-34\)

\(=\left[\left(-16\right)+16\right]+\left(24-34\right)\)

\(=0+\left(-10\right)=\left(-10\right)\)

Bài 1) Tự tính

Bài 2) a) 3x + 27 = 9

=> 3x = 9 - 27

=> 3x = -18

=> x = -18 : 3

=> x = -6

b) 2x + 12 = 3(x - 7)

=> 2x + 12 = 3x - 21

=> 2x - 3x = 21 - 12

=> -x = 9

=> x = -9

c) 2x² - 1 = 49

=> 2x² = 49 + 1

=> 2x² = 50

=> x² = 50 : 2

=> x² = 25

=> x² = 5²

=> \(\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)

Bài 3a)

Ta có: A = (-a - b + c) - (-a - b - c)

=> A = -a - b + c + a + b + c

=> A  = (-a + a) - (b - b) + (c + c)

=>  A = 2c

b) Với c = -2 thay vào biểu thức

ta được : A = 2 . (-2)

=> A = -4

hoặc với a = 1; b = -1, c = -2 thay vào biểu thức

rồi tính

Bài 4: Ta có: 6a + 1 = 2(3a - 1) + 3

Do 3a - 1 \(⋮\)3a - 1 => 2(3a - 1) \(⋮\)3a - 1

Để 6a + 1 \(⋮\)3a - 1 thì 3 \(⋮\)3a - 1 => 3a - 1 \(\in\)Ư(3) = {1; 3; -1; -3}

Lập bảng:

tự lập

61) 

a) $7-x=8-(-7)$

     $7-x=15$

        $-x=15-7$

        $-x=8$

         $x=-8$

b) $x-8=(-3)-8$.

    $x-8=(-11)$

   $x=(-11)+8$

    $x=-3$

62)

a) $\left|a\right|=2$

$a=2$; hoặc $a=-2$

b) $\left|a+2\right|$ = 0

$a+2=0$.

Do đó $a=-2$. (chuyển vế đổi dấu)

Ta có: 2x - 1 = 2(x - 2) + 3

Do x - 2 \(⋮\)x - 2 => 2(x - 2) \(⋮\)x - 2

Để 2x - 1 \(⋮\)x - 2 thì 3 \(⋮\)x - 2 => x - 2 \(\in\)Ư(3) = {1; 3; -1; -3}

Lập bảng: 

Vậy ...

2x-1\(⋮\)x-2

2x-4+3\(⋮\)x-2

2(x-2)+3\(⋮\)x-2

=>3\(⋮\)x-2(vì 2(x-2)\(⋮\)x-2)

=>x-2\(\in\)Ư(3)

=>x-2\(\in\){-1;-3;1;3}

=>x\(\in\){1;-1;3;5}

Vậyx \(\in\){1;-1;3;5}

a) -12.(x - 5) + 7(3 - x) = 5

=> -12x + 60 + 21 - 7x = 5

=> -19x + 81 = 5

=> -19x = 5 - 81

=> -19x = -76

=> x = -76 : (-19)

=> x = 4

b) (x + 1) + (x + 2) + (x + 3) + ... + (x + 20) = 250

=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 20) = 250

=> 20x + 210 = 250

=> 20x = 250 - 210

=> 20x = 40

= > x = 40 : 20

=> x = 2

\(-12\left(x-5\right)+7\left(3-x\right)=5\)

\(\Leftrightarrow-12x+60+21-7x=5\)

\(\Leftrightarrow-19x+81=5\)

\(\Leftrightarrow81-5=19x\)

\(\Leftrightarrow19x=76\)

\(\Leftrightarrow x=4\)

(2x - 7) + 17 = 6

=> 2x - 7 = 6 - 17

=> 2x - 7 = -11

=> 2x = -11 + 7

=> 2x = -4

=> x = -4 : 2

=> x = -2

+) 12 -2(3 - 3x)= -2

=> 2(3 - 3x) = 12 + 2

=> 2(3 - 3x) = 14

=> 3 - 3x = 14 : 2

=> 3 - 3x = 7

=> 3x = 3 - 7

=> 3x = -4

=> x = -4/3

\(\left(x+1\right)\left(x-3\right)=0\)

=> \(\orbr{\begin{cases}x+1=0\\x-3=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=-1\\x=3\end{cases}}\)

Vậy...

=(1+98-99-100)+(2-3-4+5)+(6-7-8+9)+...+(95-96-97+98)

=-100+0+0+0+0+0.........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................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x-32+15-3x=-4x+1-32

x-3x+4x=1-32+32-15

2x=1+32-32-15

2x=1+(32-32)-15

2x=1-15

2x=-14

x=-14:2

x= - 7

a, (- 40 - 16 + 32 ) + ( 40 + 116 - 32 )

=( - 40 )- 16 + 32 + 40 + 116 - 32

=[(-40)+40]+32-32+116-16

=0+ (32-32)+(116-16)

=0+0+100

=100

b, -15 + 5 + ( 20 - 100 - 2017 ) - ( - 15 - 2017 )

=  -15 + 5 + 20 - 100 - 2017 + 15 + 2017 

=[(-15 )+ 15] + (2017 - 2017 ) + 20-100

=0+0+(20-100)

= - 80