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2022-04-28 20:10:24
BPT ⇔ 3 x 2 − 6 x + 3 > 0 ⇔3x2−6x+3>0 ⇔ 3 ( x − 1 ) 2 > 0 ⇔3(x−1)2>0 Có ( x − 1 ) 2 ≥ 0 ∀ x (x−1)2≥0∀x . Dấu ''='' xảy ra khi x = 1 => Để 3 ( x − 1 ) 2 > 0 3(x−1)2>0 thì ( x − 1 ) 2 ≠ 0 ⇔ x ≠ 1 (x−1)2≠0⇔x≠1 Vậy 3 x 2 − 5 x − x + 3 > 0 3x2−5x−x+3>0 ⇔ x ≠ 1
2022-04-25 21:43:18
2022-04-17 09:16:26
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2022-04-17 09:16:26
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2022-04-17 09:16:26