\(\left(7-\dfrac{1}{5} +\dfrac{1}{3}\right)-\left(6+\dfrac{9}{5}+\dfrac{4}{3}\right)\)

\(=7-\dfrac{1}{5}+\dfrac{1}{3}-6-\dfrac{9}{5}-\dfrac{4}{3}\)

\(=\left(7-6\right)-\left(\dfrac{1}{5}+\dfrac{9}{5}\right)+\left(\dfrac{1}{3}-\dfrac{4}{3}\right)-\dfrac{1}{3}\)

\(=1-2+\left(-1\right)-\dfrac{1}{3}\)

\(=\left[1+\left(-1\right)\right]-2-\dfrac{1}{3}\)

\(=0-2-\dfrac{1}{3}\)

\(=-2-\dfrac{1}{3}\)

\(=-\dfrac{6}{3}-\dfrac{1}{3}\)

\(=-\dfrac{7}{3}\)

Em đăng kí nhận bằng tiền mặt.

Em đăng kí nhận thưởng câu lạc bộ chiến binh olm tháng 6 năm 2024.

Cậu chia nhỏ bài ra để được hỗ trợ nhanh hơn nhé!

$\color{#0000CD}{\text{A}}$   $\color{#0000FF}{\text{n}}$
$\color{#8A2BE2}{\text{nn}}$

\(a,\left[\left(-21,8\right)+4,125\right]+\left[11,8+\left(-2,125\right)\right]\)

\(=-21,8+4,125+11,8-2,125\)

\(=\left[\left(-21,8\right)+11,8\right]+\left(4,125-2,125\right)\)

\(=-10+2\)

\(=-8\)

\(b,\left(-124,5\right)+\left(-6,24+124,5\right)\)

\(=-124,5-6,24+124,5\)

\(=\left[\left(-124,5\right)+124,5\right]-6,24\)

\(=0-6,24\)

\(=-6,24\)

$\color{#90EE90}{\text{4}}$  $\color{#B0E0E6}{\text{56}}$

\(a,\left(-12,5\right)+3,4+12,5+\left(-3,4\right)\)

\(=\left[\left(-12,5\right)+12,5\right]+\left[3,4+\left(-3,4\right)\right]\)

\(=0+0\)

\(=0\)

\(b,32,8+4,2+\left(-4,3\right)+\left(-32,8\right)+4,3\)

\(=\left[32,8+\left(-32,8\right)\right]+\left[\left(-4,3\right)+4,3\right]+4,2\)

\(=0+0+4,2\)

\(=4,2\)

\(c,-\left(42,5+150\right).2,5-7,5.2,5\)

\(=2,5.\left(-42,5\right)-2,5.150-7,5.2,5\)

\(=2,5.\left(-42,5-150-7,5\right)\)

\(=2,5.\left(-200\right)\)

\(=-500\)

\(d,\left(-2,45\right).2,6+2,6.\left(-7,55\right)\)

\(=\left[\left(-2,45\right)+\left(-7,55\right)\right].2,6\)

\(=-10.2,6\)

\(=-26\)

Toán lớp 5 sao khó thế!

Yêu cầu để đúng lớp!

$0,125+\mathrm{3,12}+12,4$

$=\mathrm{3,245}+\mathrm{12,4}$

$=15,645$

\(0,125+3.12+12,4\)

\(=0,125+36+12,4\)

\(=36,125+12,4\)

\(=48,525\)

\(\dfrac{7}{2}+\dfrac{4}{5}\)

\(=\dfrac{35}{10}+\dfrac{8}{10}\)

\(=\dfrac{43}{10}\)