7ha 14m²

=7,0014 ha

432,8ha 

=4,328 km²

Trang

$n^{CuSO4}=\genfrac{}{}{0ex}{}{16\%.50}{100\%.160}=0,05\left(mol\right)$

Pt : $CuS{O}^4+2NaOH\to Cu{\left(OH\right)}^2+N{a}^{2}S{O}^4$

       0,05-------->0,1---------->0,05--------->0,05

a) $C{\%}^{ddNaOH}=\genfrac{}{}{0ex}{}{0,1.40}{250}.100\%=1,6\%$

b) $m^{ddspu}=50+250-0,05.98=295,1\left(g\right)$

$C{\%}^{Na2SO4}=\genfrac{}{}{0ex}{}{0,05.142}{295,1}.100\%=2,41\%$

$n^{CuSO4}=\genfrac{}{}{0ex}{}{16\%.50}{100\%.160}=0,05\left(mol\right)$

Pt : $CuS{O}^4+2NaOH\to Cu{\left(OH\right)}^2+N{a}^{2}S{O}^4$

       0,05-------->0,1---------->0,05--------->0,05

a) $C{\%}^{ddNaOH}=\genfrac{}{}{0ex}{}{0,1.40}{250}.100\%=1,6\%$

b) $m^{ddspu}=50+250-0,05.98=295,1\left(g\right)$

$C{\%}^{Na2SO4}=\genfrac{}{}{0ex}{}{0,05.142}{295,1}.100\%=2,41\%$