a,\(119+24+81=\left(119+81\right)+24=200+24=224\)

b,\(57+26+34+63=\left(57+63\right)+\left(26+34\right)=120+60=180\)

c,\(199+36+201+184+37=\left(199+201\right)+\left(36+184\right)+37=400+220+37=657\)d,\(24+36+276=\left(276+24\right)+36=300+36=336\)

e, \(\left(667+11\right)+133=\left(667+133\right)+11=800+11=811\)

f, \(287+121+515+79=\left(287+513\right)+\left(121+79\right)+2=800+200+2=1002\)

g,\(25.104=25\left(100+4\right)=2500+100=2600\)

h,\(8.7.25=\left(4+4\right).7.25=\left(4.25+4.25\right).7=\left(100+100\right).7=200.7=1400\)

i,\(16.6.125=4.4.6.125=4\left(100+25\right).24=\left(400+100\right).24=500.24=12000\)

k,\(48.125.1008=4.12.125.1008=500.12.1008=6000.1008=6000\left(1000+8\right)=6000000+48000=6048000\)

Nội thất 

cho mk xin 1 like ạ 

\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.3^8}{2^6.3^6.2^9}=\dfrac{2^{15}}{2^{6+9}}.\dfrac{3^8}{3^6}=3^2=9\)

1.\(\left(-3x+1\right)\times\dfrac{1}{2}=\left(-\dfrac{1}{2}\right)^2\Rightarrow\left(-3x+1\right)=\dfrac{1}{2}\)

\(\Rightarrow\left(-3\right)x=\dfrac{1}{2}-1\Rightarrow x=-\dfrac{1}{2}:\left(-3\right)=\dfrac{1}{6}\)

2.\(x+\dfrac{5}{4}=\dfrac{16}{\left(x+5\right)^2}\Rightarrow x\left(x+5\right)^2+\dfrac{5\left(x+5\right)^2}{4}=16\)

\(4x\left(x+5\right)^2+5\left(x+5\right)^2=64\Rightarrow4x\left(x^2+10x+25\right)+5\left(x^2+10x+25\right)-64=0\)

\(4x^3+40x^2+100x+5x^2+50x+125-64=0\)

\(4x^3+45x^2+150x+61=0\)

\(\Delta=b^2-3ac=45^2-3.4.150=225>1\) vậy phương trình có 1 nghiệm 

\(k=\dfrac{9abc-2b^3-27a^2d}{2\sqrt{\left|\Delta\right|^3}}=\dfrac{637}{125}\)

\(x=\dfrac{\sqrt{\Delta}.\left|k\right|}{3ak}.\left(\sqrt[3]{\left|k\right|+\sqrt{k^2+1}}+\sqrt[3]{\left|k\right|-\sqrt{k^2-1}}\right)-\dfrac{b}{3a}=-0,4702284538\)

3.\(\left(x+10\right)^2:\left(-2\right)=\left(-32\right)\Rightarrow\left(x+10\right)^2=16\)

\(\Rightarrow\left\{{}\begin{matrix}x+10=-4\\x+10=4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-14\\x=-6\end{matrix}\right.\)

4.\(\left(x+\dfrac{1}{2}\right)\left(x-\dfrac{1}{3}\right)=0\Rightarrow\left\{{}\begin{matrix}x+\dfrac{1}{2}=0\\x-\dfrac{1}{3}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)

Dãy số trên có số hạng là

\(\left(101-1\right):2+1=51\)

Tổng dãy số trên là

\(\left(1+101\right)\times51:2=2601\)

a, \(49.\left(-17\right)+17.\left(-51\right)=-17\left(49+51\right)\)

\(=-17.100=-1700\)

b, \(37:19+62:19=\left(37+62\right):19=\dfrac{99}{19}\)

c,\(17.\left(-21\right)+35:\left(-7\right)-2.\left(-5\right).\left(-8\right)\)

\(=17.\left(-21\right)+\left(-5\right)-2.\left(-5\right)\left(-8\right)\)

\(=17.\left(-21\right)+\left(-5\right)\left(1+\left(-2\right)\left(-8\right)\right)\)

\(=17\left(-21\right)+\left(-5\right)17=17.\left(-21+-5\right)\)

\(=17.\left(-26\right)=-442\)

a, \(\left(x+67\right)-134=0\Rightarrow x+67=134\)

\(\Rightarrow x=134-67=67\)

b,\(\left(x-213\right)+235=768\Rightarrow x-213=768-235\)

\(\Rightarrow x-213=533\Rightarrow x=746\)

c.sai đầu bài 

d, \(x-32:16=48\Rightarrow x-2=48\Rightarrow x=50\)

e, \(\left(x-32\right):16=48\Rightarrow x-32=768\Rightarrow x=800\)

f,\(1428:x=14\Rightarrow x=1428:14=102\)