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2022-05-27 17:53:25
a) 12 - 2(x + 1) = 3x - 5
=> 12 - 2x - 2 = 3x - 5
=> -2x - 3x = -5 - 12 + 2
=> -5x = -15
=> x = 3
Vậy...........
b) \(\dfrac{2}{7}\left(3x+1\right)=2+\dfrac{6}{7}x\)
=> \(\dfrac{6}{7}x+\dfrac{2}{7}=2+\dfrac{6}{7}x\)
=> \(\dfrac{6}{7}x-\dfrac{6}{7}x=2+\dfrac{2}{7}\)
=> \(0=\dfrac{16}{7}\)
Vậy pt vô nghiệm
c) x(x - 1) = (x - 2)(x + 2)
=> x2 - x = x2 + 2x - 2x - 4
=> -x - 2x + 2x = -4
=> -x = -4
=> x = 4
Vậy............
d) \(\dfrac{5x-2}{3}=\dfrac{5-3x}{2}\)
=>\(\dfrac{2\left(5x-2\right)}{6}=\dfrac{3\left(5-3x\right)}{6}\)
=> 10x - 4 = 15 - 9x
=> 10x + 9x = 15 + 4
=> 19x = 19
=> x = 1
Vậy..............
2022-03-25 20:04:02
2022-03-25 20:04:02
2022-03-25 19:41:29
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2022-03-18 10:37:58