\(\text{y là một số vừa chia hết cho 2 và 5}\) \(\Rightarrow\)\(y=0\)
\(\text{Khi đó, ta có:}\)
\(2014x0⋮9\)
\(2+0+1+4+x+0⋮9\)
\(7+x⋮9\)
\(\text{Chữ số }x\) \(\text{thỏa mãn là:}\) 2
\(\Rightarrow x=2;y=0\)
HOK TỐT VÀ TK~

chắc là 20931 là kết quả. Có thể bạn ấy thiếu dấu =

đơn giản
she visits her aunt and uncle
HOK TỐT

\(a,X\div\left(-\dfrac{1}{3}\right)^3=\dfrac{1}{9}\)

\(X\div\left(-\dfrac{1}{3}\times-\dfrac{1}{3}\times-\dfrac{1}{3}\right)=\dfrac{1}{9}\)

\(X\div\left(-\dfrac{1}{27}\right)=\dfrac{1}{9}\)

\(X=\dfrac{1}{9}\times\left(-\dfrac{1}{27}\right)\)

\(X=\dfrac{1}{9}\times\left(\dfrac{-1}{27}\right)\)
\(X=\dfrac{-1}{243}\)

\(X=-\dfrac{1}{243}\)

\(b,\left(\dfrac{4}{5}\right)^5\times X=\left(\dfrac{4}{7}\right)^7\)

\(X=\left(\dfrac{4}{7}\right)^7-\left(\dfrac{4}{7}\right)^5\)

\(X=\left(\dfrac{4}{7}\right)^{7-5}\)

\(X=\left(\dfrac{4}{7}\right)^2\)

\(X=\dfrac{4}{7}\times\dfrac{4}{7}=\dfrac{16}{49}\)

\(c,\left(X+\dfrac{1}{2}\right)^2=\dfrac{1}{64}\)
\(\left(X+\dfrac{1}{2}\right)\times\left(X+\dfrac{1}{2}\right)=\dfrac{1}{64}\)

\(\left(X+\dfrac{1}{2}\right)\times\left(X+\dfrac{1}{2}\right)=\dfrac{1}{8}\times\dfrac{1}{8}\)

\(\Rightarrow X+\dfrac{1}{2}=\dfrac{1}{8}\)

\(X=\dfrac{1}{8}-\dfrac{1}{2}=\dfrac{1}{8}-\dfrac{4}{8}=-\dfrac{3}{8}\)

\(d,\left(3X+1\right)^3=-64\)

\(\left(3X+1\right)\times\left(3X+1\right)\times\left(3X+1\right)=-4\times-4\times-4\)

\(\Rightarrow3X+1=-4\)

\(3X=\left(-4\right)-1=-\left(4+1\right)=-5\)

\(X=-5\div3=\dfrac{-5}{3}=-\dfrac{5}{3}\)
Chúc cậu học tốt~

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