tim x biet (2x-2)*(3x+6)=0
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a) (2x.6) .(3x-18) = 0
=> 2x.6 = 0 => 12x = 0 => x = 0
3x - 18 = 0 => 3x = 18 => x = 6
KL:...
b) 25 + (15-x) = 30
25 + 15 - x = 30
40 - x = 30
x = 10
\(a)\left(2x.6\right).\left(3x-18\right)=0\Leftrightarrow\hept{\begin{cases}2x.6=0\\3x-18=0\end{cases}\Leftrightarrow\hept{\begin{cases}12x=0\\3x=18\end{cases}\Leftrightarrow}\hept{\begin{cases}x=0\\x=6\end{cases}}}\)
\(b)25+\left(15-x\right)=30\Leftrightarrow15-x=5\Leftrightarrow x=20\)
tym cho mk nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^4-2x^3-2x^2+3x+2=0\)
\(\Leftrightarrow x^4-2x^3-2x^2+4x-x+2=0\)
\(\Leftrightarrow\left(x^4-2x^3\right)-\left(2x^2-4x\right)-\left(x-2\right)=0\)
\(\Leftrightarrow x^3\left(x-2\right)-2x\left(x-2\right)-\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x^3-2x-1\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x^3-x-x-1\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left[\left(x^3-x\right)-\left(x+1\right)\right]=0\)
\(\Leftrightarrow\left(x-2\right)\left[x\left(x^2-1\right)-\left(x+1\right)\right]=0\)
\(\Leftrightarrow\left(x-2\right)\left[x\left(x-1\right)\left(x+1\right)-\left(x+1\right)\right]=0\)
\(\Leftrightarrow\left(x-2\right)\left[\left(x^2-x\right)\left(x+1\right)-\left(x+1\right)\right]=0\)
\(\Leftrightarrow\left(x-2\right)\left(x+1\right)\left(x^2-x-1\right)=0\)
Đến đây ez r
![](https://rs.olm.vn/images/avt/0.png?1311)
=> |2x-1|=3x
=> 2x-1=3x hoặc 2x-1=-3x
=> x = -1 hoặc x = 1/5
k mk nha
![](https://rs.olm.vn/images/avt/0.png?1311)
- a, Do \(\left[3x-15\right]^7=0\)
=> \(3x-15=0\)
=> \(3x=0+15\)
=> \(3x=15\)
=> \(x=15:3\)
=> \(x=5\)
\(\left(3x-5\right)^7=0\)
\(\Rightarrow3x-5=0\)
\(\Rightarrow3x=5\)
\(\Rightarrow x=\frac{5}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3x\left(2x-1\right)-1-2x=0\)
\(\Leftrightarrow6x^2-3x-1-2x=0\)
\(\Leftrightarrow6x^2-5x-1=0\)
chắc bài này sai đề. sửa lại:
\(3x\left(2x-1\right)+1-2x=0\)
\(\Leftrightarrow3x\left(2x-1\right)-\left(2x-1\right)=0\)
\(\Leftrightarrow\left(3x-1\right)\left(2x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-1=0\\2x-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=\frac{1}{2}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 12+(2x-11)=53
(2x-11) = 53-12
2x-11= 41
2x=41+11
2x=52
x= 52:2
x=26
Vậy...
\(b,21-\left(-6+3x\right)=9\)
\(\Rightarrow21+6-3x=9\)
\(\Rightarrow27-3x=9\)
\(\Rightarrow3x=18\)
\(\Rightarrow x=6\)
c, -(2x+4)+11=-27
=>-2x-4+11=-27
=>-2x+7=-27
=>-2x = -34
=>x=17
d, 33-(33-x)=0
=>33-33+x=0
=>x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(2x-6).(x-2) = 0
=>2x - 6 = 0 hoặc x - 2 = 0
2x - 6 = 0
2x = 6
x = 3
x - 2 = 0
x = 2
Vậy x thuộc {2;3}
\(\left(2x-2\right).\left(3x+6\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-2=0\\3x+6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=2\\3x=-6\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=-2\end{cases}}}\)
ĐS: ...........
( 2x - 2 ) . ( 3x + 6 ) = 0
=> 2x - 2 = 0 hoặc 3x + 6 = 0
2x = 0 + 2 hoặc 3x = 0 - 6
2x = 2 hoặc 3x = - 6
x = 1 hoặc x = - 2
*Lưu ý nếu bạn học số nguyên rồi thì mới làm theo cách này nha!