\(\frac{9^{10}.5^{30}}{5^{15}.15^{15}}=\frac{3^{10}.3^{10}.5^{30}}{5^{30}.3^{15}}=\frac{3^{20}}{3^{15}}=3^5\)
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\(\frac{8}{15}+\frac{16}{30}+\frac{3}{5}+\frac{9}{10}+2\frac{3}{5}\)
\(=\frac{8}{15}+\frac{16}{30}+\frac{3}{5}+\frac{9}{10}+\frac{13}{5}\)
\(=\frac{16+16+18+27+78}{30}\)
\(=\frac{155}{30}\)
\(=\frac{31}{6}\)
Hc tốt #
\(\frac{8}{15}\)+\(\frac{16}{30}\)+\(\frac{3}{5}\)+\(\frac{9}{10}\)+2\(\frac{3}{5}\)
=\(\frac{16}{30}\)+\(\frac{16}{30}\)+\(\frac{18}{30}\)+\(\frac{27}{30}\)+\(\frac{13}{5}\)
=\(\frac{16+16+18+27}{30}\)+\(\frac{78}{30}\)
=\(\frac{77}{30}\)+\(\frac{78}{30}\)= \(\frac{155}{30}\)
ta có : (ghi lại đề)
=6+12+18+24+30/3+6+9+12+15
=2*(3/3+6/6+9/9+12/12+15/15)
=2*(1+1+1+1+1)
=2*5=10
chúc main học tốt nhé
\(a)\frac{(-5)^{60}.30^5}{15^5.5^{61}}=\frac{(5.2.3)^5}{(5.3)^5.5}=\frac{5^5.2^5.3^5}{5^5.3^5.5} =\frac{2^5}{5}=\frac{32}{5}\)
\(b) \frac{(-3)^{10}.15^5}{25^3.(-9)^7}=\frac{(-3)^{10} .(3.5)^5}{(5^2)^3.[(-3).3]^7}=\frac{(-3)^{10}.3^5.5^5}{5^6.(-3)^7.3^7}=\frac{(-3)^3}{5.3^2}=\frac{-3}{5}\)
~ Hok tốt a~
a: \(=\dfrac{5^{42}\cdot7^{30}}{5^{40}\cdot7^{30}\cdot10}=\dfrac{5^2}{10}=\dfrac{25}{10}=\dfrac{5}{2}\)
b: \(=\dfrac{3^{18}\cdot5^{10}}{5^{10}\cdot3^{10}\cdot3^9}=\dfrac{1}{3}\)
\(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\)
\(\Rightarrow\frac{3\left(5x-1\right)}{30}+\frac{5\left(2x+3\right)}{30}=\frac{2\left(x-8\right)}{30}-\frac{x}{30}\)
\(\Rightarrow15x-3+10x+15=2x-16-x\)
\(\Rightarrow24x=-28\)
\(\Rightarrow x=-\frac{7}{6}\)
\(3^5\)