a) 3x - 1 = 243b) (\(\frac{2}{3}\))x + 1 = \(\frac{8}{27}\)c) 3x + 3x + 2 = 270d) ( x - \(\frac{5}{2}\)) 2 = 144e) (2x + 1)3 = \(\frac{125}{27}\)f) (2x - 1)5 = 243g) ( x - \(\frac{1}{3}\))2 = (\(\frac{9}{4}\))-1h) (22 - 1)4 = ( 2x - 1)2i) (2x + 1)2 + (x + 1)10 =...
Đọc tiếp
a) 3x - 1 = 243
b) (\(\frac{2}{3}\))x + 1 = \(\frac{8}{27}\)
c) 3x + 3x + 2 = 270
d) ( x - \(\frac{5}{2}\)) 2 = 144
e) (2x + 1)3 = \(\frac{125}{27}\)
f) (2x - 1)5 = 243
g) ( x - \(\frac{1}{3}\))2 = (\(\frac{9}{4}\))-1
h) (22 - 1)4 = ( 2x - 1)2
i) (2x + 1)2 + (x + 1)10 = 0
k) \(\frac{x-2}{3}\)= \(\frac{x+3}{2}\)
l) \(\frac{2}{x}\)= \(\frac{x}{50}\)
m) \(\frac{x-3}{4}\)= \(\frac{4}{x+3}\)
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