Bài 2. Tính hợp lý các giá trị biểu thức sau:
- 27.99+99.35:31:2
- 76.34-19.64:38.9
- 555+-100+-80+-333
- 1000--137-263+-572+-291
- -600+253+-40+3150+-307
- 145+-217--318+-783-245+318
- 125-170+120+-125+-864-36
- 1-2+3-4+5-6+…+997-998+999-1000
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\(145+\left(-217\right)-\left(-318\right)+\left(-783\right)-245+318\)
\(=145-217+318-783-245-318\)
\(=\left(145-245\right)-\left(217+783\right)+\left(318-318\right)\)
\(=\left(-100\right)-1000+0=-1100\)
\(a,1357-\left(964+357\right)-\left(36+120\right)=1357-964-357-36-120\)
\(=1000-1000-120=-120\)
\(b,10000-\left(137+572\right)+\left(263-291\right)=10000-137-572+263-291\)
\(=10000-709-291+263=10000-1000+263=9000+263=9263\)
\(c,35\cdot125+35\cdot75-70\cdot50=35\cdot125+35\cdot75-35\cdot100\)
\(=35\cdot\left(125+75-100\right)=35\cdot100=3500\)
(\(\cdot\)là nhân nhé bạn)
\(d,2-4+6-8+...+98-100=-2-2-...-2\)
(50 số hạng -2)
\(=\left(-2\right)\cdot50=-100\)
Làm lại câu d:
\(d,2-4+6-8+...+98-1000=-2-2-...-2+98-1000\)
(49 số -2)
\(=\left(-2\right)\cdot49+98-1000=-98+98-1000=1000\)
Giải:
\(A=\left[\left(-8\right)+\left(-7\right)\right]+\left(-10\right)=\left(-15\right)+\left(-10\right)=\left(-25\right)\)
\(B=-\left(-299\right)+\left(-219\right)+\left(-401\right)+12=299-219-401+12=-309\)
\(C=555+\left(-100\right)+\left(-80\right)+\left|-333\right|=555-100-80+333=708\)
\(D=\left|-347\right|+\left(-40\right)+3150+\left(-307\right)=347-40+3150-307=2456\)
\(E=98.42-\left\{50.\left[\left(18-2^3\right):2+3^2\right]\right\}\)
\(E=4116-\left\{50.\left[\left(18-8\right):2+9\right]\right\}\)
\(E=4116-\left\{50.\left[10:2+9\right]\right\}\)
\(E=4116-\left\{50.\left[5+9\right]\right\}\)
\(E=4116-\left\{50.14\right\}\)
\(E=4116-700\)
\(E=3416\)
\(F=-80-\left[-130-\left(12-4^2\right)\right]+2008^0\)
\(F=-80-\left[-130-\left(12-16\right)\right]+1\)
\(F=-80-\left[-130-\left(-4\right)\right]+1\)
\(F=-80-\left(-126\right)+1\)
\(F=47\)
\(G=1000+\left(-670\right)+297+\left(-330\right)=1000-670+297-330=297\)
\(H=1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\)
\(H=2^{10}:2^4+140:\left(38+32\right)-7^2\)
\(H=2^6+140:70-49\)
\(H=64+2-49\)
\(H=17\)
\(I=\left|-129\right|-119+\left|2-31\right|=129-119+\left|-29\right|=10+29=39\)
\(K=219+573+381-173\)
\(K=\left(219+381\right)+\left(573-173\right)\)
\(K=600+400\)
\(K=1000\)
\(L=36.33-105.11+22.15\)
\(L=36.33-35.3.11+11.2.3.5\)
\(L=36.33-35.33+33.10\)
\(L=33.\left(36-35+10\right)\)
\(L=33.11\)
\(L=363\)
\(N=160-\left(2^3.5^2-6.25\right)\)
\(N=160-\left[25.\left(8-6\right)\right]\)
\(N=160-\left[25.2\right]\)
\(N=160-50\)
\(N=110\)
\(O=\left(44.52.60\right):\left(11.13.15\right)=137280:2145=64\)
\(P=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).\left(2^4-4^2\right)=\left(2^{17}+15^4\right).\left(3^9-2^{17}\right).0=0\)
\(Q=100+98+96+...+4+2-97-95-...-3-1\)
\(Q=100+\left(98-97\right)+\left(96-95\right)+...+\left(4-3\right)+\left(2-1\right)\)
\(Q=100+1+1+...+1+1\)
Vì có 98:2=49 số 1
\(\Rightarrow Q=100+49\)
\(Q=149\)
1000 - {(-137) - [263 + (-572) + (-291)]}
= 1000 - [-137 - (263 - 572 - 291)]
= 1000 - [-137 - (-600)]
= 1000 - (-137 + 600)
= 1000 - 463
= 537
#Học tốt
~NTTH~
1000 - ( 137 + 572 ) + ( 263 - 291 )
= 1000 - 709 + ( - 28 )
= 291 + ( -28 )
= 263
1000-(137+572)+(263-291)
=1000-137-572+263-291
=1000-(137-263)-(572+291)
=1000-(-126)-863
=263
Chúc bạn học tốt!
Mấy bài này dễ màNguyễn Thanh Hằng