(5𝑥−1)(𝑥+3)−(𝑥−2)(5𝑥−4)
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a: \(5x^4-x^3+7x\)
\(=x\left(5x^3-x^2+7\right)\)
c: \(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a. $x(x^2-5)=x^3-5x$
b. $3xy(x^2-2x^2y+3)=3x^3y-6x^3y^2+9xy$
c. $(2x-6)(3x+6)=6x^2+12x-18x-36=6x^2-6x-36$
d.
$(x+3y)(x^2-xy)=x^3-x^2y+3x^2y-3xy^2=x^3+2x^2y-3xy^2$
Bài 2:
a.
\((2x+5)(2x-5)=(2x)^2-5^2=4x^2-25\)
b.
\((x-3)^2=x^2-6x+9\)
c.
\((4+3x)^2=9x^2+24x+16\)
d.
\((x-2y)^3=x^3-6x^2y+12xy^2-8y^3\)
e.
\((5x+3y)^3=(5x)^3+3.(5x)^2.3y+3.5x(3y)^2+(3y)^3\)
\(=125x^3+225x^2y+135xy^2+27y^3\)
f.
\((5-x)(25+5x+x^2)=5^3-x^3=125-x^3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,\\ a,=x^3-5x\\ b,=3x^3y-6x^3y^2+9xy\\ c,=6x^2-6x-36\\ d,=x^3+2x^2y-3xy^2\\ 2,\\ a,=4x^2-25\\ b,=x^2-6x+9\\ c,=9x^2+24x+16\\ d,=x^3-6x^2y+12xy^2-8y^3\\ e,=125x^3+225x^2y+135xy^2+27y^3\\ f,=125-x^3\)
\(g,=8y^3+x^3\\ 3,\\ a,=x\left(x+2\right)\\ b,=\left(x-3\right)^2\\ c,=\left(x-y\right)\left(y+5\right)\\ d,=2x\left(y+1\right)-y\left(y+1\right)=\left(2x-y\right)\left(y+1\right)\\ e,=6x^2y^2\left(xy^2+2y-3x\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+\dfrac{4}{5}\times\dfrac{3}{8}=\dfrac{3}{2}\)
\(x+\dfrac{3}{10}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}-\dfrac{3}{10}\)
\(x=\dfrac{12}{10}=\dfrac{6}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5x2 + 15x - x - 3 - 5x2 + 4x + 10x - 8 = 28x -11
\(\left(5x-1\right)\left(x+3\right)-\left(x-2\right)\left(5x-4\right)\)
\(=5x^2+14x-3-5x^2+14x-8\)
\(=28x-11\)