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![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án cần chọn là: C
Ta có 2018(x−2018)=2018
x–2018=2018:2018
x–2018=1
x=2018+1
x=2019x
Vậy x=2019.
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án là C
Ta có: 2018.(x - 2018) = 2018
⇔ x - 2018 = 2018 : 2018
⇔ x - 2018 = 1
⇔ x = 2019
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án: C
2018 . (x – 2018) = 2018
(x – 2018) = 1
x = 1+2018
x = 2019
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ \(A=2018\cdot2018\)
\(=\left(2019-1\right)\cdot2018=2019\cdot2018-2018\)
\(B=2017\cdot2019\)
\(=\left(2018-1\right)\cdot2019=2018\cdot2019-2019\)
\(\Rightarrow A>B\)
b/
\(A=2018\cdot2019\)
\(=\left(2017+1\right)\cdot2019=2017\cdot2019+2019\)
\(B=2017\cdot2020\)
\(=2017\cdot\left(2019+1\right)=2017\cdot2019+2017\)
\(\Rightarrow A>B\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow\left(x-2018\right)^{x+1}-\left(x-2018\right)^{x+1}.\left(x-2018\right)^{10}=0\)
\(\Leftrightarrow\left(x-2018\right)^{x+1}\left(1-\left(x-2018\right)^{10}\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-2018\right)^{x+1}=0\\1-\left(x-2018\right)^{10}=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-2018=0\\\left(x-2018\right)^{10}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2018\\x=2019\end{matrix}\right.\)
Đáp án là C
có: 2018.(x - 2018) = 2018
⇔ x - 2018 = 2018 : 2018
⇔ x - 2018 = 1
⇔ x = 2019