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a2 - 4a + 3
= a2 - a - 3a + 3
= a.(a - 1) - 3.(a - 1)
= (a - 1).(a - 3)
= \(a^2-3a-a+3\)= \(a\left(a-3\right)-\left(a-3\right)\)= \(\left(a-3\right)\left(a-1\right)\)
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a) \(\left(x-7\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
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a) 3x2 + 10x + 8
= 3x2 + 6x + 4x + 8
= 3x.(x + 2) + 4.(x + 2)
= (x + 2).(3x + 4)
b) 2x2 + x - 6
= 2x2 + 4x - 3x - 6
= 2x.(x + 2) - 3.(x + 2)
= (x + 2).(2x - 3)
a) \(\left(3x+4\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
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a) x(x - 2) + x - 2
= x(x - 2) + (x - 2)
= (x - 2).(x + 1)
b) 5x(x - 3) - x + 3
= 5x(x - 3) - (x - 3)
= (x - 3).(5x - 1)
a.x(x-2)+x-2
=(x-2)(x+1)
b.5x(x-3)-x+3
=5x(x-3)-(x-3)
=(x-3)(5x-1)
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a/ 5x2-x+5xy-y
= 5x(x+y) - (x+y)
= (5x-1) (x+y)
b) 2xz + 3z + 6y + xz
= ko bt làm
a; x(5x-1)+y(5x-1)
=>( x+y).(5x-1)
b; có ghi sai đề ko vậy ; toàn x vs z thế