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1 - 2 + 3 - 4 + 5 - 6 +...+ 99 - 100
= ( 1- 2 ) + ( 3 - 4 ) + ( 5 - 6 ) +....+ ( 99- 100)
= 1 + 1 + 1 +....+1 ( 50 c/s 1 )
= 1. 50
=50
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\(\dfrac{3}{5}:\left(\dfrac{1}{4}.\dfrac{7}{5}\right)=\dfrac{3}{5}:\dfrac{7}{20}\)
\(=\dfrac{60}{35}=\dfrac{12}{7}\)
=> D
Câu 3 : \(\dfrac{-6}{11}=>\dfrac{-11}{6}\)
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\(\begin{array}{l}\frac{{ - 3}}{4}.\left( {\frac{2}{3} - \frac{2}{6}} \right) = \frac{{ - 3}}{4}.\left( {\frac{4}{6} - \frac{2}{6}} \right)\\ = \frac{{ - 3}}{4}.\frac{2}{6} = \frac{{ - 6}}{{24}} = \frac{{ - 1}}{4}\end{array}\)
=> Chọn D.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(...=2022+2020+\left(-2019+2016-2018+2015-2017+2014\right)+...+\left(6-3+5-2+4-1\right)\)
\(=2022+2020+\left(-3-3-3\right)+\left(-3-3-3\right)+...+\left(-3-3-3\right)+\left(-3-2-1\right)\)
\(=2022+2020+\left(-9\right)+\left(-9\right)+...\left(-9\right)+\left(-6\right)\)
\(=2022+2020+\left(-9\right).\left[\left(2019-9\right):6+1\right].\left[\left(2019+6\right)\right]:2+\left(-6\right)\)
\(=2022+2020+\left(-9\right).336.2025:2+\left(-6\right)\)
\(=2022+2020-3061800-6\)
\(=-3057764\)
Chọn đáp án C