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a) \(\left(3-x\right)\left(5x+10\right)=0\)
\(\left(3-x\right).5.\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3-x=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
vậy...
b) \(\left|5x+2\right|-4x=7\)
\(\left|5x+2\right|=7+4x\)
\(\Rightarrow\orbr{\begin{cases}5x+2=7+4x\\5x+2=-7-4x\end{cases}}\Rightarrow\orbr{\begin{cases}5x-4x=7-2\\5x+4x=-7-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\9x=-9\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)
vậy....
k nha
a, \(\left(3-x\right)\left(5x+10\right)=0\)
\(\Rightarrow3-x=0\) hoặc \(5x+10=0\)
\(\Rightarrow x=3\) hoặc \(x=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Theo đề, ta có: \(\dfrac{1+2x}{18}=\dfrac{1+4x}{34}\)
\(\Leftrightarrow34\left(1+2x\right)=18\left(1+4x\right)\)
\(\Leftrightarrow34+68x=18+72x\)
\(\Leftrightarrow34-18=72x-68x\)
\(\Leftrightarrow16=4x\)
\(\Leftrightarrow x=4\)
Khi \(x=4\) vào ta có: \(\dfrac{1+4.4}{34}=\dfrac{1+6.4}{2y^2}\Leftrightarrow\dfrac{1}{2}=\dfrac{25}{2y^2}\)
\(\Leftrightarrow2y^2=50\)
\(\Leftrightarrow y^2=50\)
\(\Leftrightarrow y=\pm5\)
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Bài 4:
a: 8/9x=8/7
nên x=8/7:8/9=9/7
b: x:7/2=2/5
nên x=2/5x7/2=14/10=7/5
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2:
a: =>x=-3/10+4/5=-3/10+8/10=5/10=1/2
b: =>12,5x=0,25
=>x=1/50
c: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
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a: =1-1/2+1/2-1/3+...+1/100-1/101
=1-1/101=100/101
b: =1/3-1/7+1/7-1/11+...+1/107-1/111
=1/3-1/111
=108/333=12/37
c: =3(3/8*11+3/11*14+...+3/197*200)
=3(1/8-1/11+1/11-1/14+...+1/197-1/200)
=3*192/1600=9/25
d: =1/3-1/5+1/5-1/7+...+1/19-1/21
=1/3-1/21
=7/21-1/21=6/21=2/7
\(936-\left(4x+5x\right)=900\\ 936-9x=900\\ 9x=36\\ x=4\)