Question

[Trần Thảo Linh]

Tính giá trị các biểu thức

a. \(A=\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)                                  c. \(C=\dfrac{72^3.54^2}{108^4}\)

b. \(B=\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)                                d. \(D=\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

Answer 1

[Nguyễn Thị Thương Hoài]

a; A = \(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\) = \(\dfrac{3^{10}.\left(11+5\right)}{3^9.2^4}\) = \(\dfrac{3^{10}.16}{3^9.16}\) = 3

b; B = \(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\) 

= \(\dfrac{2^{10}.\left(13+65\right)}{2^8.104}\) 

= \(\dfrac{2^{10}.78}{2^8.2^2.26}\) 

= \(\dfrac{2^{10}.26.3}{2^{10}.26}\) 

= 3 

Answer 2

[Nguyễn Thị Thương Hoài]

b; B = \(\dfrac{2^{10}.13+3^{10}.5}{3^9.2^4}\)

    B =  \(\dfrac{3^{10}.\left(13+5\right)}{3^9.2^4}\)

    B =  \(\dfrac{3^{10}.18}{3^9.2^4}\) 

    B =  \(\dfrac{3^{10}.3^2.2}{3^9.2^4}\)

    B =   \(\dfrac{3^{12}.2}{3^9.2^4}\)

    B =    \(\dfrac{3^3}{2^4}\) 

    B = \(\dfrac{27}{8}\)