Rút gon biểu thức a) A = (\(\sqrt{x}\) - \(\frac{1}{\sqrt{x}}\) ) : (\(\frac{\sqrt{x}-1}{\sqrt{x}}\) + \(\frac{1-\sqrt{x}}{x+\sqrt{x}}\)) b ) B = (\(\frac{\sqrt{a}}{2}\) - \(\frac{1}{2\sqrt{a}}\) ) ( \(\frac{a-\sqrt{a}}{\sqrt{a}+1}\) - \(\frac{a+\sqrt{a}}{\sqrt{a}-1}\))Các bạn ơi giúp mk...
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Rút gon biểu thức
a) A = (\(\sqrt{x}\) - \(\frac{1}{\sqrt{x}}\) ) : (\(\frac{\sqrt{x}-1}{\sqrt{x}}\) + \(\frac{1-\sqrt{x}}{x+\sqrt{x}}\))
b ) B = (\(\frac{\sqrt{a}}{2}\) - \(\frac{1}{2\sqrt{a}}\) ) ( \(\frac{a-\sqrt{a}}{\sqrt{a}+1}\) - \(\frac{a+\sqrt{a}}{\sqrt{a}-1}\))
Các bạn ơi giúp mk nha
nhầm \(A=\frac{\left(\sqrt{x}+1\right)^2}{\sqrt{x}}\)
a)Điều kiện xác định:\(x>0\)
A\(=\left(\frac{x-1}{\sqrt{x}}\right):\left(\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)+1-\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}\right)\)
=\(\frac{x-1}{\sqrt{x}}.\frac{\sqrt{x}\left(\sqrt{x}+1\right)}{x-1+1-\sqrt{x}}\)
=\(\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}}.\frac{\sqrt{x}\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}=\left(\sqrt{x}+1\right)^2\)