Question

[♥๖Lan_Phương_cute#✖#girl_học_đường๖...]

tính bằng cách thuận tiện 

a)  \(\frac{8}{13}\)+ \(\frac{4}{9}\) + \(\frac{1}{3}\)+ \(\frac{5}{13}\)+ \(3\)

b)  \(\frac{8}{5}\) x \(\frac{4}{7}\) + \(\frac{4}{7}\) x \(\frac{2}{5}\)- \(1\)

Answer 1

[tuyền đào]

a)\(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{1}{3}\right)+3\)

\(=1+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3\)

\(=1+3+\frac{7}{9}\)

\(=4\frac{7}{9}\)

\(=\frac{43}{9}\)

b)\(\frac{8}{5}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{2}{5}-1\)

\(=\frac{4}{7}\cdot\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}\cdot2-1\)

\(=\frac{8}{7}-1\)

\(=\frac{1}{7}\)

Answer 2

[Lê Quang Phúc]

a) \(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3=4\frac{7}{9}\)

b)\(\frac{8}{5}.\frac{4}{7}+\frac{4}{7}.\frac{2}{5}-1\)

\(=\frac{4}{7}.\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}.2-1\)

\(=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)