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23 tháng 2 2022

`Answer:`

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16 tháng 5 2022

⇒ Đáp án: C. Nghề trồng rau

16 tháng 5 2022

Mìnk nghĩ lè C.nghề trồng rau

19 tháng 3 2022

\(\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{1}{3}\Rightarrow\dfrac{x}{27}=-\dfrac{1}{9}\Rightarrow\dfrac{x}{27}=\dfrac{-3}{27}\Rightarrow x=27\)

19 tháng 3 2022

\(\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{1}{3}=-\dfrac{1}{9}\Rightarrow x=-\dfrac{1}{9}.27=-3\).

28 tháng 6 2023

\(a.2^{x+2}-2^x=96\\ 2^x\cdot4-2^x=96\\ 2^x\cdot\left(4-1\right)=96\\ 2^x\cdot3=96\\ 2^x=96:3\\ 2^x=32\\ 2^x=2^5\\ =>x=5\)

 

\(2^{x+1}\cdot3^y=12^x\\ 2^{x+1}\cdot3^y=3^x\cdot2^{2x}\\ \left\{{}\begin{matrix}2^{x+1}=2^{2x}\\3^y=3^x\end{matrix}\right.\\ \left\{{}\begin{matrix}x+1=2x\\y=x\end{matrix}\right.\\ \left\{{}\begin{matrix}x=1\\y=x=1\end{matrix}\right.\\ \left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)

\(c.10^x:5^y=20^y\\ 10^x:5^y=5^y\cdot4^y\\ 10^x=10^{2y}\\ =>x=2y\)

 

1 tháng 4 2022

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17 tháng 7 2021

a) \(A=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}-\dfrac{1}{x-\sqrt{x}}\right):\left(\dfrac{1}{\sqrt{x}+1}+\dfrac{2}{x-1}\right)\)

\(=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\left(\dfrac{1}{\sqrt{x}+1}+\dfrac{2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\right)\)

\(=\dfrac{x-1}{\sqrt{x}\left(\sqrt{x}-1\right)}:\dfrac{\sqrt{x}-1+2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}:\dfrac{\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\sqrt{x}+1}{\sqrt{x}}:\dfrac{1}{\sqrt{x}-1}=\dfrac{\sqrt{x}+1}{\sqrt{x}}.\left(\sqrt{x}-1\right)=\dfrac{x-1}{\sqrt{x}}\)

b) \(A=2\Rightarrow\dfrac{x-1}{\sqrt{x}}=2\Rightarrow x-1=2\sqrt{x}\Rightarrow x-2\sqrt{x}-1=0\)

\(\Rightarrow x-2\sqrt{x}+1=2\Rightarrow\left(\sqrt{x}-1\right)^2=2\Rightarrow\left[{}\begin{matrix}\sqrt{x}-1=\sqrt{2}\\\sqrt{x}-1=-\sqrt{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\sqrt{x}=\sqrt{2}+1\\\sqrt{x}=1-\sqrt{2}\left(l\right)\end{matrix}\right.\Rightarrow x=\left(\sqrt{2}+1\right)^2=3+2\sqrt{2}\)

c) \(A< 0\Rightarrow\dfrac{x-1}{\sqrt{x}}< 0\) mà \(\sqrt{x}>0\Rightarrow x-1< 0\Rightarrow x< 1\Rightarrow0< x< 1\)

13 tháng 7 2021

1 will go

2 are going to do

3 has studied

4 has been

5 Did they put

6 has worked 

7 will go camping

9 haven't met

10 are going to have - will have

11 received 

12 won't plau

13 has lived

14 will come

15 has just decided

16 have ever seen

17 have meet

18 visited

19 playing

20 to ride