tìm x | 3x+1|-17=-12
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![](https://rs.olm.vn/images/avt/0.png?1311)
Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
7+x=-16
x=-16-7
x=-23
2) 2x – 35 = 15
2x=15+35
2x=50
x=50:2
x=25
3) 3x + 17 = 12
3x=12-17
3x=-5
x=-5/3
4) (2x – 5) + 17 = 6
2x-5=6-17
2x-5=-11
2x=-11+5
2x=-6
x=-6:2
x=-3
5) 10 – 2(4 – 3x) = -4
2(4-3x)=10-(-4)
2(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
6) - 12 + 3(-x + 7) = -18
3(-x+7)=-18-(-12)
3(x+7)=-6
x+7=-6:3
x+7=-2
x=-2-7
x=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x+17=12
=>3x=12-17
=>3x=-5
=>x=-5:3
=>x=-1,66
/x-1/=0
=>x-1=0
=>x =0+1
=>x =1
-13./x/=-26
=>/x/=-26:(-13)
=>/x/=2
=>x=-2 hoặc x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 4(x+1)-(3x+1)=14
<=>4x+4-3x-1=14
<=>4x-3x = 14-4
<=>x=10
b) -12(x-5) +7.(3x)=5
<=> -12x +60 + 21+7x=5
<=> -12x+7x=5-60-21
<=> -5x=-76
<=> x=76/5
c) 17x + 34 -4x+28-9x=82
<=> 17x-9x-4x=82-34-28
<=> 4x=20
<=> x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{-12}{17}< \dfrac{x}{17}< \dfrac{-8}{17}\)
\(\Rightarrow-12< x< -8\)
\(\Rightarrow x\in\left\{-11;-10;-9\right\}\)
b) \(\dfrac{-1}{2}< x< \dfrac{5}{3}\)
\(\Rightarrow\dfrac{-3}{6}< x< \dfrac{10}{6}\)
\(\Rightarrow x\in\left\{\dfrac{-2}{6};\dfrac{-1}{6};0;\dfrac{1}{6};...;\dfrac{7}{6};\dfrac{8}{6};\dfrac{9}{6}\right\}\)
c) \(3,456< x\le7,89\)
\(\Rightarrow x\in\left\{3,456;3,457,3,458;...;7,89\right\}\)
d) \(5,82< \overline{5,8x0}< 8,845\)
\(\Rightarrow x\in\left\{3;4\right\}\)
e) \(32,82< \overline{3x,850}< 35,845\)
\(\Rightarrow x\in\left\{3;4\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\left|3x+1\right|-17=-12\)
\(\Rightarrow\left|3x+1\right|=-12+17\)
\(\Rightarrow\left|3x+1\right|=5\)
\(\Rightarrow\hept{\begin{cases}3x+1=5\\3x+1=-5\end{cases}}\Rightarrow\hept{\begin{cases}3x=4\\3x=-6\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{4}{3}\\x=-2\end{cases}}\)
Do đó,\(x\in\left\{\frac{4}{3};-2\right\}\)
\(b,2x+\left|x-2\right|=7\)
\(\Rightarrow2x+x-2=7\)
\(\Rightarrow3x=7+2\)
\(\Rightarrow3x=9\)
\(\Rightarrow x=3\)
c, Tương tự như trên
a)|3x+1|-17=-12
|3x+1| = -12+17
|3x+1| =5
=>3x+1=5 hoặc 3x+1= -5
+)3x+1=5
3x =5-1
3x =4
x =4:3
x =4/3
+)3x+1= -5
3x =-5-1
3x = -6
x = -6:3
x =-2
Vậy x=4/3,x= -2
K HỘ NHA
![](https://rs.olm.vn/images/avt/0.png?1311)
(x−3)(x2+3x+9)−(3x−17)=x3−12
⇔x3−27−3x+17−x3+12=0
⇔2−3x=0
⇔3x=2⇒x=23
| 3x+1|-17=-12
| 3x+1|=-12+17
|3x+1|=5
=>3x+1 thuộc {5;-5}
=>3x thuộc {4;-6}
Do 3x chia hết cho 3 nên 3x=-6
x=-6:3=-2
Vậy x=-2