25 + 14 = ??
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CG
3
14 tháng 6 2021
Ta có : \(14-\left(25-x\right)+\left(-14+50\right).14-\left(25-x\right)+\left(-14+50\right)\)
\(=14-25+x+36.14-25+x-14+50\)
\(=2x+36.14=2x+504\)
14 tháng 6 2021
14−(25−x)+(−14+50).14−(25−x)+(−14+50)14−(25−x)+(−14+50).14−(25−x)+(−14+50)
=14−25+x+36.14−25+x−14+50=14−25+x+36.14−25+x−14+50
=2x+36.14=2x+504
Hok tốt!
NA
12 tháng 3 2022
\(a.=\dfrac{2019}{2020}\times\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)\\ =\dfrac{2019}{2020}\times1=\dfrac{2019}{2020}\\ b.=\dfrac{25}{27}\times\left(\dfrac{17}{14}-\dfrac{1}{14}-\dfrac{2}{14}\right)\\ =\dfrac{25}{27}\times1=\dfrac{25}{27}\)
DV
1
AH
Akai Haruma
Giáo viên
6 tháng 2
Lời giải:
\(\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+(\frac{-3}{14})^1\\
=\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+\frac{-3}{14}\\
=\frac{-3}{14}(1+\frac{-12}{25}+1)=\frac{-3}{14}.\frac{38}{25}=\frac{-57}{175}\)
20 tháng 6 2017
\(\text{Ta có : }\)\(\frac{25}{4.9}+\frac{25}{9.14}+\frac{25}{14.19}+......+\frac{25}{2004.2009}\)
\(=5.\left(\frac{5}{4.9}+\frac{5}{9.14}+\frac{5}{14.19}+......+\frac{5}{2004.2009}\right)\)
\(=5\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+......+\frac{1}{2004}-\frac{1}{2009}\right)\)
\(=5\left(\frac{1}{4}-\frac{1}{2009}\right)\)
\(=5.\frac{2005}{8036}=\frac{10025}{8036}\)
11 tháng 5 2022
|
1) \( 2155 – (174 + 2155) + (-68 + 174) = -68\) 2) \(-25 . 72 + 25 . 21 – 49 . 25=-2500\) 3) \(35.(14 –23) – 23.(14–35)=168\) 4) \(8154 – (674 + 8154) + (–98 + 674)=-98\) 5) \(25.21+25.72+49.25=2399\) 6) \(27.(13-16)-16.(13-27)=143\) 7) \(–1911 – (1234 – 1911) =-1234\) |
HQ
Hà Quang Minh
Giáo viên
5 tháng 10 2023
a, \(\begin{array}{l}A = \dfrac{{ - 3}}{{14}} + \dfrac{2}{{13}} + \dfrac{{ - 25}}{{14}} + \dfrac{{ - 15}}{{13}}\\A = \left( {\dfrac{{ - 3}}{{14}} + \dfrac{{ - 25}}{{14}}} \right) + \left( {\dfrac{2}{{13}} + \dfrac{{ - 15}}{{13}}} \right)\\A = \dfrac{{ - 3 + \left( { - 25} \right)}}{{14}} + \dfrac{{2 + \left( { - 15} \right)}}{{13}}\\A = \dfrac{{ - 28}}{{14}} + \dfrac{{ - 13}}{{13}}\\A = - 2 + (-1)\\A = - 3\end{array}\)
b,
Cách 1:
\(\begin{array}{l}B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \left( {\dfrac{5}{3}.\dfrac{7}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}} \right) + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = 0 + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\end{array}\)
Cách 2:
\(B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \dfrac{5}{3}.({\dfrac{7}{{25}} -\dfrac{7}{{25}} + \dfrac{{21}}{{25}}})\\B = \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\)
25 + 14 =39
Nha bạn
25+14=39