x + 3,5 - 4/7 = 1/2 - 4 \(\frac{1}{8}\)
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\(x+3,5-\frac{4}{7}=\frac{3}{2}-5\frac{1}{8}\)
=> \(x+\frac{35}{10}-\frac{4}{7}=\frac{3}{2}-\frac{41}{8}\)
=> \(x+\frac{7}{2}-\frac{4}{7}=\frac{12}{8}-\frac{41}{8}\)
=> \(x+\frac{7}{2}-\frac{4}{7}=-\frac{29}{8}\)
=> \(x+\frac{7}{2}=-\frac{29}{8}+\frac{4}{7}=-\frac{171}{56}\)
=> \(x=-\frac{171}{56}-\frac{7}{2}=-\frac{367}{56}\)
Trả lời:
\(x+3,5-\frac{4}{7}=\frac{3}{2}-5\frac{1}{8}\)
\(\Leftrightarrow x+\frac{7}{2}-\frac{4}{7}=\frac{3}{2}-\frac{41}{8}\)
\(\Leftrightarrow x+\frac{7}{2}-\frac{4}{7}=\frac{-29}{8}\)
\(\Leftrightarrow x+\frac{7}{2}=\frac{-171}{56}\)
\(\Leftrightarrow x=\frac{-367}{56}\)
Vậy \(x=\frac{-367}{56}\)
a) \(1\frac{2}{7} = 1 + \frac{2}{7} = \frac{9}{2}\)
\(\begin{array}{l}x:1\frac{2}{7} = - 3,5\\x:\frac{9}{7} = - \frac{7}{2}\\x = - \frac{7}{2}.\frac{9}{7}\\x = - \frac{9}{2}\end{array}\)
b) \(0,4.x - \frac{1}{5}.x = \frac{3}{4}\)
\(\begin{array}{l}\frac{2}{5}.x - \frac{1}{5}.x = \frac{3}{4}\\\left( {\frac{2}{5} - \frac{1}{5}} \right).x = \frac{3}{4}\\\frac{1}{5}.x = \frac{3}{4}\\x = \frac{3}{4}:\frac{1}{5}\\x = \frac{3}{4}.5\\x = \frac{{15}}{4}\end{array}\)
1) \(\left(\frac{7}{8}-\frac{3}{4}\right).1\frac{1}{3}-\frac{2}{7}.\left(3,5\right)^2\)
= \(\frac{1}{8}.\frac{4}{3}-\frac{2}{7}.\frac{49}{4}\) = \(\frac{-10}{3}\)
2) \(\frac{5}{4}:\frac{1}{2}-\frac{3}{4}\) = \(\frac{7}{4}\)
2)
\(\left|3,5-x\right|+\frac{2}{7}=\frac{16}{7}\)
\(\Rightarrow\left|3,5-x\right|=\frac{16}{7}-\frac{2}{7}\)
\(\Rightarrow\left|3,5-x\right|=2\)
\(\Rightarrow\left[{}\begin{matrix}3,5-x=2\\3,5-x=-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3,5-2\\x=3,5+2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1,5\\x=5,5\end{matrix}\right.\)
Vậy \(x\in\left\{1,5;5,5\right\}.\)
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Bài 2 :
1) \(x-70=-45\) 2) \(\frac{4}{7}:x=\frac{12}{28}\)
\(\Rightarrow\) \(x=-45+70\) \(\Rightarrow x=\frac{4}{7}:\frac{12}{28}\)
\(\Rightarrow\) \(x=25\) \(\Rightarrow x=\frac{4}{3}\)
Vậy \(x=25\) Vậy \(x=\frac{4}{3}\)
3) Giống câu c) ở bài 1
4) \(x-50=-35\) 5) \(\frac{4}{7}.x=\frac{11}{18}\)
\(\Rightarrow x=-35+50\) \(\Rightarrow x=\frac{11}{28}:\frac{4}{7}\)
\(\Rightarrow x=15\) \(\Rightarrow x=\frac{77}{72}\)
Vậy \(x=15\) Vậy \(x=\frac{77}{72}\)
6) \(\left(\frac{2}{3}x+2,5\right):2\frac{2}{6}=6\)
\(\Rightarrow\)\(\left(\frac{2}{3}x+2,5\right):\frac{14}{6}=6\)
\(\Rightarrow\) \(\frac{2}{3}x+2,5=6.\frac{14}{6}\)
\(\Rightarrow\frac{2}{3}x+2,5=14\)
\(\Rightarrow\frac{2}{3}x=\frac{23}{2}\)
\(\Rightarrow x=\frac{23}{2}:\frac{2}{3}\)
\(\Rightarrow x=\frac{69}{4}\)
Vậy \(x=\frac{69}{4}\)
Bài 1:
1) \(\frac{7}{5}+\frac{-8}{5}=-\frac{1}{5}\)
2) \(-\frac{6}{5}.\frac{15}{24}=-\frac{3}{4}\)
3) \(\left(\frac{2}{3}+1,5\right)-3,5:7\frac{1}{2}=\)\(\frac{13}{6}-\frac{7}{15}=\frac{17}{10}\)
4) \(\frac{5}{8}-\frac{-7}{9}=\frac{5}{8}+\frac{7}{9}=\frac{101}{72}\)
5)\(\frac{-7}{3}.\frac{12}{28}=-1\)
a, \(-1,8:\left(1-\frac{3}{4}\right)\)
\(=-\frac{9}{5}:\frac{1}{4}\)
\(=-\frac{36}{5}\)
b, \(\left(\frac{7}{8}-\frac{3}{4}\right)\cdot1\frac{1}{3}-\frac{2}{7}\cdot\left(3,5\right)^2\)
\(=\left(\frac{7}{8}-\frac{6}{8}\right)\cdot\frac{4}{3}-\frac{2}{7}\cdot12.25\)
\(=\frac{1}{8}\cdot\frac{4}{3}-\frac{2}{7}\cdot\frac{49}{4}\)
\(=\frac{1}{6}-\frac{7}{2}\)
\(=\frac{1}{6}-\frac{21}{6}\)
\(=-\frac{20}{6}\)
\(=-\frac{10}{3}\)
\(x+3,5-\frac{4}{7}=\frac{1}{2}-4\frac{1}{8}\)
\(x+\frac{7}{2}-\frac{4}{7}=\frac{1}{2}-\frac{33}{8}\)
\(x+\left(\frac{7}{2}-\frac{4}{7}\right)=\frac{4}{8}-\frac{33}{8}\)
\(x+\left(\frac{49}{14}-\frac{8}{14}\right)=\frac{-29}{8}\)
\(x+\frac{41}{14}=\frac{-29}{8}\)
\(x=\frac{41}{14}-\frac{-29}{8}\)
\(x=\frac{-39}{56}\)
The Angry sai dòng thứ 6 thì phải
\(x=-\frac{29}{8}-\frac{41}{14}\)
\(x=-\frac{203}{56}-\frac{164}{56}\)
\(x=\frac{39}{56}\)