1+1/2+1/4+1/8+1/16+1/32+1/64+......+1/512+1/1024=????
Giups mk với mk đang gấp các bạn cho mk câu trả lời ngay bây giờ nhé thanks....
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1+2+4+8+16+32+64+128+256+512+1024+2048
=1+(2+8)+(4+16)+(32+128)+(64+256)+(512+2048)+1024
=1+10+20+160+320+2560+1024
=4095
1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512 + 1024 + 2048 = 4095
k nha công chúa nụ cười =_= ^_^
2A=1+1/2+1/4+1/8+1/16+1/32+1/64
2A-A=(1+1/2+1/4+1/8+1/16+1/32+1/64)-(1/2+1/4+1/8+1/16+1/32+1/64+1/128)
A=1-1/128
A=127/128
A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
suy ra: 2A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
2A - A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 - 1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64 - 1/128
A = 1 - 1/128 = 127/128
hok tốt
A=1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64
A=1- bạn gạch chéo từ 1/2(đầu tiên) đến 1/32 nha
A=1-1/64=65/64.
B=Bạn làm tương tự như trên nha
k mik nha. Thanks. Chúc bạn học tốt!!!
a) A=1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
2A=1+1/2+1/4 + 1/8 + 1/16 + 1/32
2A-A= 1+1/2+1/4+1/8+1/16+1/32-(1/2+1/4+1/8+1/16+1/32+1/64)
A= 1-1/64=63/64
b) B= 1/4+1/8+1/16+......+1/512
2B= 1/2+1/4+1/8+1/16+......+1/256
2B-B=1/2+1/4+1/8+1/16+.....+1/256-(1/4+1/8+1/16+.....+1/512)
B=1/2-1/512=255/512
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#)Giải :
\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{512}\)
\(=\frac{255}{512}\)
Lời giải
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{512}\)
\(=\frac{255}{512}\)
Từ 6 giờ sáng nay đén 7 giờ ngày mai là : (12 - 6) + 7 = 13 giờ
Bây giờ là : 13 giờ : (4 + 1) = 2 giờ 36 phút
Từ 6 giờ sáng nây đến 7 giờ ngày mai là : (12 - 6) + 7 = 13 giờ
Bây giờ là : 13 * 1/4 = 3 giờ 15 phút
gọi A=1/2+1/4+1/8+...+1/1024
2xA=1+1/2+1/4+.....+1/512
2xA-A=(1+1/2+1/4+....+1/512)-(1/2+1/4+1/8+...+1/1024)
A=1-1/1024
=1023/1024
vậy A=1023/1024
\(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+...+\frac{1}{512}-\frac{1}{1024}=1-\frac{1}{1024}=\frac{1023}{1024}\)
\(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+...+\frac{1}{512}+\frac{1}{1024}=??????????\)
\(< =>1+\frac{1}{1\cdot2}+\frac{1}{2\cdot2}+\frac{1}{2\cdot4}+...+\frac{1}{2\cdot256}+\frac{1}{2\cdot512}\)
\(< =>1+\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+...+\frac{1}{2}-\frac{1}{256}+\frac{1}{2}-\frac{1}{512}\)
\(< =>1+\frac{1}{1}-\frac{1}{512}\)
\(< =>\frac{1023}{512}\)
chuc ban hoc tot nhe :))