tính bằng cách thuận tiện
a 1990 x 1993 - 1000 / 1992 x 1990 + 990\
b 2/5 x 3/4 x 5/6 : 3/4
c 132 x 145 + 100 / 145 x 133 - 45
d (36 + 54 ) x 7 + 7 x 9 + 7
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a) Tính bằng cách thuận tiện nhất:
134 x 4 x 5
= 134 x (4 x 5)
= 134 x 20 = 1680
5 x 36 x 2
= 36x (5 x 2)
= 36 x 10 = 360
42 x 2 x 7 x5
= (42 x 7) x (2 x5)
= 294 x 10 = 2940
b) 137 x 3 + 137 x 97
= 137 x (3 + 97)
= 137 x 100 = 13700
94 x 12 + 94 x 88
= 94 x (12 + 88)
= 94 x 100 = 9400
428 x 12 - 428 x 2
= 428 x (12 - 2) = 4280
537 x 39 - 537 x 19
= 537 x (39 - 19)
= 537 x 20 = 10740
a. 3/5 + 6/11 + 7/13 + 2/5 + 16/11 + 19/13
= ( 3/5 + 2/5 ) + ( 6/11 + 16/11 ) + ( 7/13 + 19/13)
= 1 + 2 + 2
= 5.
=0:{2+4+6+...98}=0
=[1+3+5+7+...97+99]x[45x3-45x3]
=[----------------------------]x0=0
Dấu gạch trên là gì đấy?
a, [ 0 x 1 x 2 x 3 ...x 99 x 100] : [2 + 4 + 6 + ... 98]
Vì có chữ số 0 mà 0 nhân số nào cũng bằng 0
=> 0 : ( 2 + 4 + 6 + ... 98 )
Vì số nào chia 0 cũng bằng 0
=> 0 : ( 2 + 4 + 6 +.. + 98 ) = 0
b, Đặt A = 1 + 3 + 5 + 7 + ... + 97 + 99 )
Đặt B = 45x 3 - 45 x 2 - 45
B = 45 x 3 - 45 x 2 - 45
B = 45 x 3 - 45 x 2 - 45 x 1
B = 45 x ( 3 - 2 - 1 )
B = 45 x 0
B = 0
Vì 0 nhân số nào cũng = 0
=> ( 1 + 3 + 5 + 7 + ... + 97 +99 ) x 0 = 0
c, Bạn chỉ cần biến đổi tử số hoặc mẫu số giống nhau thì kết quả sẽ = 1 nha
a) \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{16}{11}+\frac{19}{13}\)
\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{16}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)\)
\(=1+2+2=5\)
b) \(\frac{1995}{1997}x\frac{1990}{1993}x\frac{1997}{1994}x\frac{1993}{1995}x\frac{997}{995}=\frac{1995x1990x1997x1993x997}{1997x1993x1994x1995x995}=\frac{1990x997}{1994x995}=\frac{995x2x997}{997x2x995}=1\)
a) =(3/5+2/5)+(6/11+16/11)+(19/13+7/13)
=5/5+22/11+26/13
=1+2+3
=6
\(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{16}{11}+\frac{19}{13}\)
\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}\frac{16}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)\)
\(=1+2+2\)
\(=5\)
Bài 1
a; \(\dfrac{7}{19}\) x \(\dfrac{1}{3}\) + \(\dfrac{7}{19}\) x \(\dfrac{2}{3}\)
= \(\dfrac{7}{19}\) x (\(\dfrac{1}{3}+\dfrac{2}{3}\))
= \(\dfrac{7}{19}\) x 1
= \(\dfrac{7}{19}\)
b; 15 x \(\dfrac{2121}{4343}\) + 15 x \(\dfrac{212121}{434343}\)
= 15 x \(\dfrac{21}{43}\) + 15 x \(\dfrac{21}{43}\)
= 15 x \(\dfrac{21}{43}\) x (1 + 1)
= 15 x \(\dfrac{21}{43}\) x 2
= (15 x 2) x \(\dfrac{21}{43}\)
= 30 x \(\dfrac{21}{43}\)
= \(\dfrac{630}{43}\)
a) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}\)
\(=\dfrac{5}{7}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)
\(=\dfrac{5}{7}\times1\)
\(=\dfrac{5}{7}\)
b) \(\dfrac{1}{10}+\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{9}{10}-1\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{1}{10}+\dfrac{9}{10}-1\right)\)
\(=1+0\)
\(=1\)
c) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}+\dfrac{2}{7}\)
\(=\dfrac{5}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\dfrac{2}{7}\)
\(=\dfrac{5}{7}+\dfrac{2}{7}\)
\(=1\)
d) \(\dfrac{2}{7}+\dfrac{2}{8}+\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{4}{7}\)
\(=\left(\dfrac{2}{8}+\dfrac{1}{4}\right)+\left(\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{4}{7}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{1}{4}\right)+1\)
\(=\dfrac{1}{2}+1\)
\(=\dfrac{3}{2}\)
e) \(\dfrac{4}{5}+\dfrac{3}{10}+\dfrac{2}{10}+0,7\)
\(=\dfrac{4}{5}+\dfrac{5}{10}+\dfrac{7}{10}\)
\(=\dfrac{4}{5}+\dfrac{12}{10}\)
\(=\dfrac{4}{5}+\dfrac{6}{5}\)
\(=\dfrac{10}{5}\)
\(=2\)
g) \(362\times728+326\times272\)
\(=326\times\left(728+272\right)\)
\(=326\times1000\)
\(=326000\)
\(a.145\times565+145\times54+56\times145\)
\(=145\times\left(565+54+56\right)\)
\(=145\times675\)
\(=97875\)
\(b.225\times104\)
\(=\left(100+4\right)\times225\)
\(=22500+900\)
\(=23400\)
\(c.1000:\left(20\times25\right)\)
\(=1000:500\)
\(=2\)
\(d.\left(206\times20\right):2\)
\(=206\times\left(20:2\right)\)
\(=206\times10=2060\)
a.\(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b.\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
c.\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
a) 2/3 x 4/9 + 2/3 x 5/9
=2/3 x ( 4/9 + 5/9)
= 2/3 x 1
= 2/3
b, 7/5 x 3/4 - 1/2 x 3/4
= ( 7/5 - 1/2 ) x 3/4
= 9/10 x 3/4
= 21/40
c, ( 5/6 + 5/8 ) x 2/3
= 35/24 x 2/3
= 35/36