phân tich thành nhân tử : 5x-xy+y^2-5y
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\(x^2+xy-5x-5y=\left(x^2+xy\right)-\left(5x+5y\right)\)
\(=x\left(x+y\right)-5\left(x+y\right)=\left(x-5\right)\left(x+y\right)\)
x(x+y)-5(x+y) = (x-5)(x+y) bài này mik hok qua rùi mik đang ôn tập nên là mik tự làm chứ ko chép mấy câu trả lời khác
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5x^2+10xy+5y^2
=5.(x2+2xy+y2)
=5.(x+y)2
x^3-6x^2+9x
=x.(x2-6x+9)
=x.(x-3)2
xy+y^2-x-y
=y.(x+y)-(x+y)
=(x+y)(y-1)
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a)x2-xy+x-y
=x(x-y)+(x-y)
=(x+1)(x-y)
b)3x2-3xy-5x+5y
=3x(x-y)-5(x-y)
=(3x-5)(x-y)
a ) \(x^2-xy+x-y\).
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x-y\right)\left(x+1\right).\)
b ) \(3x^2-3xy-5x+5y\)
\(=3x\left(x-y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(3x-5\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b ) 5 x ( x - 1 ) - 3x ( x - 1 )
= ( 5x - 3x ) ( x - 1 )
= 2x ( x - 1 )
c ) x ( x + y ) - 5 x - 5y
= x ( x + y ) - 5 ( x + y )
= ( x - 5 ) (x + y )
d ) x ^ 2 + xy + x
= x ( x + y + 1 )
e ) x ( x - y ) + y ( y - x )
= x ( x - y ) - y ( x - y )
= ( x - y ) ( x -y )
= ( x - y ) 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 5x(x-1)-3x(x-1)=(5x-3x)(x-1)=2x(x-1)
b, x(x+y)-5x-5y=x(x+y)-5(x+y)=(x-5)(x+y)
c, x2+xy+x=x(x+y+1)
d, x(x-y)+y(y-x)=x(x-y)-y(x-y)=(x-y)(x-y)=(x-y)2
b)5x(x-1)-3x(x-1)=x(x-1).(5-3)=x(x-1).2
c)x(x+y)-5x-5y=x(x+y)-(5x+5y)=x(x+y)-[5(x+y)[=(x+y).(x-5)
d)x^2+xy+x=x(x+y+1)
e)x(x-y)+y(y-x)=x(x-y)-(x-y).y=(x-y).(x-y)
5x - xy + y2 - 5y
= ( 5x - 5y ) - ( xy - y2 )
= 5( x - y ) - y( x - y )
= ( 5 - y )( x - y )
\(5x-xy+y^2-5y\)
\(=\left(5x-5y\right)-\left(xy-y^2\right)\)
\(=5\left(x-y\right)-y\left(x-y\right)\)
\(=\left(x-y\right)\left(5-y\right)\)