Tìm x biết : (x+5) (x-2) < 0
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( x - 10 ) ^2 = 5^2
=> x - 10 = 5
=> x = 5 + 10
=> x = 15
\(\left(x-10\right)^2=5^2\)
\(\Leftrightarrow\left(x-10\right)^2-5^2=0\)
\(\Leftrightarrow\left(x-10-5\right)\left(x-10+5\right)=0\)
\(\Leftrightarrow\left(x-15\right)\left(x-5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-15=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}}\)
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( 3x - 6 )^2 = 36
=> ( 3x - 6 )^2 = 6^2
=> 3x - 6 = 6
=> 3x = 6 + 6
=> 3x = 12
=> x = 12 : 3
=> x = 4
( 3x - 6 )2 =36
3x - 6 = 36
3x = 36 +6
3x = 42
x = 42 : 3
x = 14
Vậy x = 14
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\(\left(x+2\right)+\left(x+3\right)=x\)
\(\Leftrightarrow x+2+x+3=x\)
\(\Leftrightarrow2x+5=x\)
\(\Leftrightarrow2x-x=-5\)
\(\Leftrightarrow x=-5\)
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\(\left(2x-4\right)^{2018}=0\)
\(\Rightarrow2x-4=0\)
\(\Leftrightarrow2x=4\)
\(\Leftrightarrow x=2\)
=> ( 2x - 4 ) ^ 2018 = 0 ^ 2018
=> 2x- 4 = 0
=> 2x = 0 + 4
=> 2x = 4
=> x = 4 : 2
=> x = 2
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(1+2)+[(-3)+(-4)]+...+[(-999)+(-1000)]
=3-7+11-...-1999
=(3-7)+(11-15)+...+(1995-1999)
=-4+(-4)+...+(-4)
=-4.250
=-1000
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BÌNH 1 BÌNH 2
3l 5l
3l 0l
0l 3l
3l 3l
1l 5l ( đổ 2l từ B1 vào B2 )
1l 0l
0l 1l
3l 1l
0l 4l
XONG RỒIIIIIIIII
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0;\(\pm4;\pm8;\pm12;....\)
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\(\left[\left(46-32\right)^2-\left(54-42\right)^2\right]\cdot36-1872\)
\(=\left[\left(14\right)^2-12^2\right]\cdot36-1872\)
\(=\left(196-144\right)\cdot36-1872\)
\(=52\cdot36-1872\)
\(=1872-1872\)
\(=0\)
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2<x<5
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