\(\dfrac{3^{18}.24^4}{18^4.9^5}=\dfrac{3^{18}.6^4.4^4}{3^4.6^4.\left(3^2\right)^5}\\ =\dfrac{3^{18}.6^4.4^4}{3^4.6^4.3^{10}}\\ =\dfrac{3^{18}.6^4.4^4}{3^{14}.6^4}=3^4.4^4=12^4\)

\(\dfrac{3^{18}.24^4}{18^4.9^5}=\dfrac{3^{18}.3^4.8^4}{9^4.2^4.9^5}=\dfrac{3^{22}.\left(2^3\right)^4}{\left(3^2\right)^9.2^4}=\dfrac{3^{22}.2^{12}}{3^{18}.2^4}=3^4.2^8\)

\(3^x+3^{x+1}+3^{x+2}=117\)

\(3^x\left(1+3+3^2\right)=117\)

\(3^x=\dfrac{117}{13}=9=3^2\)

\(\Rightarrow x=2\)

Cám ơn bạn nha

Ta có:

\(3^x+3^{x+1}+3^{x+2}=117\)

\(\Leftrightarrow3^x+3^x.3+3^x.3^2=117\)

\(\Leftrightarrow3^x\left(1+3+3^2\right)=117\)

\(\Leftrightarrow3^x.13=117\Leftrightarrow3^x=9\Leftrightarrow3^x=3^2\)

\(\Leftrightarrow x=2\)

Vậy...

Cám ơn nha

Ta có \(x^2\ge0;\left|x-1\right|\ge0\)

\(\Rightarrow x^2+\left|x-1\right|\ge0\)

\(\Rightarrow\) |x² + |x-1|| = x²+|x-1|

\(\Rightarrow x^2+\left|x-1\right|=x^2+2\Leftrightarrow\left|x-1\right|=2\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Cám ơn bạn

\(\Delta ABC=\Delta HIK\)

\(\Rightarrow\left\{{}\begin{matrix}AB=HI;BC=IK;AC=HK\\\widehat{A}=\widehat{H};\widehat{B}=\widehat{I};\widehat{C}=\widehat{K}\end{matrix}\right.\)

như vậy ta có thể suy ra được:

\(HI=2cm;IK=40cm;\widehat{I}=40^0\)

a, Cạnh tương ứng với canh BC là cạnh IK

Góc tương ứng với góc H là góc : góc A

b, các cạnh bằng nhau là: AB = HI; AC = HK ; BC = IK

các cặp góc bằng nhau là: góc A = góc H; góc B = góc I; góc C = góc K

mình cứ xét riêng từng cái 1 nhé

\(\dfrac{0,8:\left(\dfrac{4}{5}.1,25\right)}{0,65-\dfrac{1}{25}}=\dfrac{0,8:1}{0,61}=\dfrac{80}{61}\)

\(\dfrac{\left(1,08-\dfrac{2}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{17}}+\left(1,2.0,5\right):\dfrac{-4}{5}=\dfrac{1:\dfrac{4}{7}}{\dfrac{119}{36}.\dfrac{36}{17}}+\dfrac{3}{5}:\left(-\dfrac{4}{5}\right)\)

\(=\dfrac{\dfrac{7}{4}}{7}+-\dfrac{3}{4}=\dfrac{23}{2}\)

cộng và ta có KQ:/1563/122

Hình như bạn làm sai rồi

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