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a) x- 25%x= 1/2<=>x-1/4x=1/2<=>3/4x=1/2<=>x=1/2:3/4=2/3
b)\(\left(50\%x+2\frac{1}{4}\right).\frac{-2}{3}=\frac{17}{6}\Leftrightarrow-\frac{1}{3}x-\frac{3}{2}=\frac{17}{6}\Leftrightarrow x=-13\)
c)\(\left(3\frac{x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\Leftrightarrow\frac{28+x}{7}:\left(-4\right)=\frac{-1}{28}\Leftrightarrow\frac{28+x}{-28}=\frac{1}{-28}\Leftrightarrow28+x=1\Leftrightarrow x=-27\)
d)\(\left(1\frac{1}{3}-25\%-\frac{5}{12}\right)-2x=1,6:\frac{3}{5}\Leftrightarrow\frac{2}{3}-2x=\frac{8}{3}\Leftrightarrow x=-1\)
a)x-25%x=1/2
x-1/4x=1/2
x.(1-1/4)=1/2
x.3/4=1/2
x=1/2:3/4
x=2/3
a)50 + x = 180 - 120
50 + x = 60
x = 60-50
x = 10
b)20-x = 150-140
20-x = 10
x = 20-10
x = 10
c) 25+x = 100-40
25+x=60
x= 60-25
x=35
d) 100+x =130-25
100+x = 105
x = 105-100
x = 5
e) 143+x = 174-22
143+x = 152
x = 152-143
x = 9
ỦNG HỘ MK NHÁ
120 + ( 50 + x ) = 180
50 + x = 180 - 120
50 + x = 60
x = 60 - 50
x = 10
140 + ( 20 - x ) = 150
20 - x = 150 - 140
20 - x = 10
x = 20 - 10
x = 10
100 - ( 25 + x ) = 40
25 + x = 100 - 40
25 + x = 60
x = 60 - 25
x = 35
130 - ( 100 + x ) = 25
100 + x = 130 - 25
100 + x = 105
x = 105 - 100
x = 5
174 - ( 143 + x ) = 22
143 + x = 174 - 22
143 + x = 152
x = 152 - 143
x = 9
k mk nha
Thanks nhìu
nhầm
\(\frac{\frac{\frac{2}{5}}{4}}{\frac{\frac{5}{25}}{50}}=\frac{\frac{\frac{2}{5}}{4}}{10}=\frac{\frac{2}{25}}{2}=\frac{4}{25}\)
\(\frac{\frac{\frac{2}{5}}{4}}{\frac{\frac{5}{25}}{50}}=\frac{\frac{2}{5}:4}{\frac{5}{25}:50}=\frac{\frac{2}{5}.\frac{1}{4}}{\frac{5}{25}.\frac{1}{50}}=\frac{\left(\frac{1}{10}\right)}{\left(\frac{1}{250}\right)}=\frac{1}{10}:\frac{1}{250}=\frac{250}{10}=25\)
\(\frac{\frac{\frac{2}{5}}{4}}{\frac{5}{\frac{25}{50}}}=\frac{\frac{2}{5}:4}{5:\frac{25}{50}}=\frac{\frac{2}{5}.\frac{1}{4}}{5.\frac{50}{25}}=\frac{\left(\frac{1}{10}\right)}{10}=\frac{1}{10}:10=\frac{1}{10}.\frac{1}{10}=\frac{1}{100}\)
Chú ý: dấu gạch ngang viết dài hơn để phân biệt tử số và mẫu số của phân số
a: \(20-\left[30-\left(5-1\right)^2\right]\)
\(=20-\left[30-4^2\right]\)
\(=20-14=6\)
b: \(71+\dfrac{50}{5+3\left(57-6\cdot7\right)}\)
\(=71+\dfrac{50}{5+3\cdot\left(57-42\right)}\)
\(=71+\dfrac{50}{5+3\cdot15}=71+\dfrac{50}{50}=72\)
c: \(4\cdot\left\{270:\left[50-\left(2^5+45:5\right)\right]\right\}\)
\(=4\cdot\left\{270:\left[50-32-9\right]\right\}\)
\(=4\cdot\left\{\dfrac{270}{50-41}\right\}=4\cdot\dfrac{270}{9}=4\cdot30=120\)
d: \(411-\left[\dfrac{\left(107+3\right)}{5}-2^2\right]\)
\(=411-\left[\dfrac{110}{5}-4\right]\)
=410-22+4
=410-18
=392
e: \(450-5\left[3^2\left(7^5:7^3-41\right)-12\right]+18\)
\(=450-5\left[9\cdot\left(7^2-41\right)-12\right]+18\)
\(=450-5\cdot\left[9\cdot8-12\right]+18\)
=468-5*60
=468-300
=168
f:
\(102-150:\left[18-2\cdot\left(10-8\right)^2\right]+1018^0\)
\(=102-150:\left[18-2\cdot4\right]+1\)
\(=103-\dfrac{150}{18-8}=103-15=88\)
A)\(75\%.x-\frac{3}{2}:\frac{5}{4}=3\frac{1}{2}+25\%\)
<=>\(\frac{3}{4}x-\frac{6}{5}=\frac{7}{2}+\frac{1}{4}\)
<=>\(\frac{3}{4}x=\frac{7}{2}+\frac{1}{4}+\frac{6}{5}\)
<=>\(\frac{3}{4}x=\frac{99}{20}\)
<=>\(x=\frac{33}{5}\)
B)\(\left(x-\frac{3}{4}\right).50\%-\frac{2}{7}=1+\frac{3}{4}\)
<=>\(\left(x-\frac{3}{4}\right)\cdot\frac{1}{2}=\frac{7}{4}\)
<=>\(\frac{1}{2}x-\frac{3}{8}=\frac{7}{4}\)
<=>\(\frac{1}{2}x=\frac{17}{8}\)
<=>\(x=\frac{17}{4}\)
C)\(\left(\frac{5}{6}-2\frac{1}{2}\right):x=\frac{2}{5}-\frac{1}{3}\)
<=>\(-\frac{5}{3}:x=\frac{1}{15}\)
<=>\(x=-\frac{25}{3}\)
D)\(\left(\frac{1}{4}-x\right)-\frac{1}{2}=2\frac{1}{2}+1\)
<=>\(\frac{1}{4}-x-\frac{1}{2}=\frac{7}{2}\)
<=>\(-\frac{1}{4}-x=\frac{7}{2}\)
<=>\(x=-\frac{15}{4}\)
4 × 125 × 25 × 8
= (4 × 25) × (125 × 8)
= 100 × 1000
= 100 000
2 × 8 × 50 × 25 × 125
= (2 × 50) × (8 × 125) × 25
= 100 × 1000 × 125
= 12 500 000
2 × 3 × 4 × 5 × 50 × 25
= (2 × 50) × (4 × 25) × (3 × 5)
= 100 × 100 × 15
= 150 000
25 × 20 × 125 × 8 - 8 × 20 × 5 × 125
= 8 × 125 × 20 × (25 - 5)
= 1000 × 20 × 20
= 400 000
- (25 x 4) x (125 x8)=100 x 1000 =100000
- (50 x 2) x (8 x 125) x 25=100 x 1000 x 25 =2500000
- (2 x 50 ) x (4 x 25) x (3 x5)=100 x 100 x 15=150000
- 25 x 20 x125 x 8 - 5
= (20 x 5) x (125 x 8) -25=100 x 1000 -5 =100000 - 5 =99995
a) `27 .75 + 25.27 -150`
`=27 xx (75 + 25)-150`
`=27 xx 100-150`
`=2700-150`
`=2550`
b) `142-[50-(2^3 .10-2^3 .5)]`
`=142-[50-2^3 .(10-5)]`
`=142-(50-8 .5)`
`=142-(50-40)`
`=142-10`
`=132`
c) `375:{32-[4+(5.3^2-42)]}-14`
`=375:{32-[4+(45-42)]}-14`
`=375:[32-(4+3)]-14`
`=375: 25 -14`
`=15-14`
`=1`
a. 27 . 75 + 25 . 27 - 150
= 27. (75 + 25) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b. 142 - [50 - (23.10 - 23.5)]
= 142 - [50 - (8 . 10 - 8 . 5)]
= 142 - {50 - [8 . (10 - 5)]}
= 142 - (50 - 40)
= 142 - 10
= 132
c. 375 : {32 – [ 4 + (5. 32 – 42)]} – 14
= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14
= 375 : {32 – [ 4 + (45 – 42)]} – 14
= 375 : {32 – [ 4 + 3]} – 14
= 375 : {32 –7} – 14
= 375 : 25 - 14
= 15 - 14
= 1
\(150-\left(5.x-25\right)=50\)
\(5.x-25=150-50\)
\(5.x-25=100\)
\(5.x=100+25\)
\(5.x=125\)
\(x=125:5\)
\(x=25\)
150-(5x-25)=50
=>5x-25=150-50=100
=>5x=100+25=125
=>x=125:5=25