Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(0,125.\left(a+1\right)^3-1=\left[0,5\left(a+1\right)\right]^3-1^3=\left(0,5a+0,5-1\right)\left(0,5a+0,5+1\right)=\left(0,5a-0,5\right)\left(0,5a+1,5\right)=0,5\left(a-1\right).0,5\left(a+0,3\right)=0,25\left(a-1\right)\left(a+3\right)\)
\(0,125.\left(a+1\right)^3-1=\left(0,5a+0,5\right)^3-1=\left(0,5a+0,5-1\right)\left[\left(0,5a+0,5\right)^2+\left(0,5a+0,5\right)+1\right]=0,5\left(a-1\right)\left(0,25a^2+0,5a+0,25+0,5a+0,5+1\right)=\left(0,5a-0,5\right)\left(0,25a^2+a+1,75\right)\)
\(0,125\left(a+1\right)^3-1\)
\(=\left[0,5\left(a+1\right)\right]^3-1\)
\(=\left(0,5a+0,5\right)^3-1^3\)
\(=\left(0,5a-0,5\right)\left[\left(0,5a+0,5\right)^2+0,5a+0,5+1\right]\)
\(=\left(0,5a-0,5\right)\left[\left(0,5a+0,5\right)^2+0,5a+1,5\right]\)
d.\(\left(5x\right)^3+\left(y^2\right)^3=\left(5x+y\right)\left(25x^2-5xy^2+y^4\right)\)
e.\(\left[0,5\left(a+1\right)\right]^3-1^3=\left[0,5\left(a+1\right)-1\right]\left\{\left[0,5\left(a+1\right)\right]^2+0,5\left(a+1\right)+1^2\right\}\)
\(=\left(0,5a+0,5-1\right)\left[0,25\left(a^2+2a+1\right)+0,5a+0,5+1\right]=\left(0,5a-0,5\right)\left(0,25a^2+0,5a+0,25+0,5a+1,5\right)\)\(=0,5\left(a-1\right)\left(0,25a^2+a+1,75+\right)=0,5\left(a-1\right).0,25\left(a^2+4a+7\right)=0,125\left(a-1\right)\left(a^2+4a+7\right)\)
CHÚC BẠN HỌC TỐT NHA !!!!
Nhớ T I C K nha cảm ơn